Scalars and Vectors
Imagine you are guiding a rescue helicopter by radio, and all you can tell the pilot is:
"They're 5 km from home." The pilot still has no idea where to fly.
5 km north? 5 km out to sea? The distance alone is useless — a
circle of possible spots 10 km wide. What the pilot actually needs is 5 km, on a bearing
of north-east: a size and a direction. Only then does one number point at one
place.
That is the whole idea of this page. Physics splits every measurable quantity into two families.
Some quantities are complete with just a size — "2 kg", "40 °C", "3 hours".
Others are only half-told until you add a direction — "5 km north", "300 m/s
upwards", "20 N to the left". The first family are scalars; the second are
vectors. Getting them straight is the key that unlocks
velocity and acceleration,
forces and momentum — because those are all vectors, and vectors don't add up the way plain numbers do.
Two families: scalars and vectors
Here are the two definitions, as plainly as they can be put:
-
A scalar has only a magnitude (a size, a number with a unit).
There is no arrow to draw — the quantity is finished as soon as you say how much.
-
A vector has a magnitude and a direction. Miss out
the direction and you have only told half the story.
The GCSE quantities you need to sort into these two boxes are:
-
Scalars (size only): distance, speed,
mass, time, energy,
temperature.
-
Vectors (size + direction): displacement,
velocity, acceleration, force (including
weight), momentum.
Notice the neat pairing that runs down the two lists: distance pairs with
displacement, and speed pairs with velocity. In
each pair the scalar is "how much", and the vector is "how much, and which way". That pairing is
worth a card of its own — but first, how do we draw a vector?
Drawing a vector as an arrow
A vector is perfectly captured by a single arrow, and the arrow does two jobs at
once:
- its length stands for the magnitude — a longer arrow means a
bigger quantity, drawn to a chosen scale (say 1 cm on paper = 1 N of force);
- the way it points — marked by the arrowhead — stands for the
direction.
So a force of 10\ \text{N} to the right is drawn twice as long as a
force of 5\ \text{N} to the right, and a force of the same
10\ \text{N} pointing up is the same length but turned a
quarter-circle. Two arrows are the same vector only if they have both the same
length and the same direction — change either one and you have a different vector. This is exactly
the free-body arrows you drew for
resultant force: every
force is a vector, so every force is an arrow.
The word scalar comes from the Latin scala, a ladder or
scale — a scalar is just a rung on a scale, a plain reading like temperature. The word
vector comes from the Latin for a carrier (the same root as a disease
"vector" that carries an illness), because a vector carries something from one place to
another — it has somewhere to go. Both names were pinned down in the 1840s by the Irish
mathematician William Rowan Hamilton, who was so pleased with the idea that he scratched his new
equations into the stone of a Dublin bridge. Next time you write a little arrow over a symbol,
you're using notation that started with a burst of excitement on a canal towpath.
The two classic pairs: distance/displacement and speed/velocity
Distance is how far you have travelled in total — the reading on a pedometer,
which only ever goes up. It is a scalar. Displacement is the straight-line vector
from where you started to where you finished, with its direction. Walk all the way round a
400\ \text{m} running track and stop where you began: your
distance is 400\ \text{m}, but your
displacement is 0\ \text{m} — you ended up exactly
where you set off, so there is no arrow to draw at all.
Worked example — there and back. You walk 3\ \text{km}
east, then turn and walk 1\ \text{km} back west.
- Distance travelled: 3 + 1 = 4\ \text{km} (you add
every step you took).
- Displacement: 3 - 1 = 2\ \text{km east} (start to
finish, in a stated direction).
The same split applies to speed and velocity. Speed is a scalar
— just "how fast", a number with a unit. Velocity is a vector — speed with a direction. A
plane cruising at 300\ \text{m/s} due north and one
cruising at 300\ \text{m/s} due south have the
same speed but opposite velocities — and if they're at the same height that
difference is the difference between a safe flight and a head-on crash. Direction is not a
decoration; it changes what happens.
These three catch almost everyone out:
-
Speed is a scalar, velocity is a vector. A car going round a roundabout at a
steady 30\ \text{km/h} has a constant speed but a
changing velocity, because its direction keeps turning. A changing velocity is an
acceleration
— which is why you're pushed sideways in your seat even though the speedometer never moves.
-
Distance is not displacement. Distance only ever grows; displacement can
shrink, and can even fall back to zero if you return to your start. "How far you went" and "how
far you ended up from home" are different questions with different answers.
-
You cannot just add the magnitudes of two vectors. Two
3\ \text{N} forces only make 6\ \text{N}
if they point the same way. Point them opposite ways and they make
0\ \text{N}; at right angles they make about
4.2\ \text{N}. The directions decide the sum — always.
Adding vectors along a line
When two vectors lie along the same straight line, combining them is easy — you
just have to respect the arrowheads. Pick one direction to call positive (say
"right is +"), then:
- Vectors pointing the same way? Add their magnitudes; the
resultant points that way too.
- Vectors pointing opposite ways? Subtract the smaller from the
bigger; the resultant points the way the bigger one pointed.
The single combined vector is called the resultant.
Worked example 1 — a tail-wind. A plane flies at
250\ \text{m/s} east and a wind blows it a further
30\ \text{m/s} east. Same direction, so add:
250\ \text{m/s} + 30\ \text{m/s} = 280\ \text{m/s east.}
Worked example 2 — a head-wind. The same plane flies
250\ \text{m/s} east but now into a
30\ \text{m/s} westward wind. Opposite directions, so subtract:
250\ \text{m/s} - 30\ \text{m/s} = 220\ \text{m/s east.}
Worked example 3 — a swimmer against the current. A swimmer moves at
2\ \text{m/s} forwards while a river current pushes them
3\ \text{m/s} backwards along the same line. Taking forwards as
positive:
(+2\ \text{m/s}) + (-3\ \text{m/s}) = -1\ \text{m/s},
a resultant of 1\ \text{m/s} backwards — the current wins, and
the swimmer is carried downstream. The minus sign didn't need decoding by hand: it simply announced
the direction.
Vectors at right angles: build a triangle
What if two vectors are not on the same line — say one points
north and one points east? You can't add or subtract them along a
line, because they're neither helping nor fighting directly. Instead you lay them
tip-to-tail: draw the first arrow, then start the second arrow from the first
one's head. The resultant is the single arrow from the very start to the very end
— the slanted third side of the triangle.
When the two vectors are at right angles, that triangle is right-angled, so its
longest side (the resultant) is found with Pythagoras:
R = \sqrt{a^2 + b^2}.
Worked example — a boat crossing a river. A boat is driven
4\ \text{m/s} straight across a river while the current sweeps it
3\ \text{m/s} downstream, at right angles to its heading. Its resultant
velocity over the ground has magnitude
R = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5\ \text{m/s},
pointing off at an angle between "across" and "downstream" — a tidy 3-4-5 triangle. (You can also
find that resultant without any algebra: draw both arrows to scale on graph paper, complete the
triangle, and measure the long side with a ruler. That's a scale drawing, and it
gives the same 5\ \text{m/s}.) The rule to carry away:
same-line vectors add or subtract, but vectors at an angle build a triangle.
Go back to that rescue helicopter. Say the lost hikers are truly 5 km from the
base, and the pilot guesses "north" and flies there. If the hikers were actually 5 km
east, the pilot is now the full width of the triangle away from them:
the gap between "5 km north" and "5 km east" is the diagonal,
\sqrt{5^2 + 5^2} \approx 7.1\ \text{km} — further than the
original 5 km. A missing direction didn't just fail to help; the wrong guess made things worse.
This is why mountain rescue, air-traffic control and satellite navigation all deal in
vectors, never bare distances. A magnitude tells you how big the problem is; only
the direction tells you where to point.
Try it: add two vectors tip-to-tail
Set the "across" and "up" parts of two vectors \mathbf{a} (blue) and
\mathbf{b} (green) with the sliders. The green arrow is drawn
tip-to-tail, starting where the blue one ends, and the bold
resultant \mathbf{a}+\mathbf{b} is the arrow straight
from the origin to the final tip. Its length — the magnitude — is measured live above.
- Make both vectors point the same way along a line (set their "up" parts to 0):
the resultant is just the two lengths added.
- Point them opposite ways along the line: the resultant is the
difference.
- Make one purely across and the other purely up: you get a
right-angled triangle, and the resultant is the Pythagoras hypotenuse — try
(4, 0) and (0, 3) for a
5.