Wave–Particle Duality
For two hundred years physicists argued about what light is. Newton pictured a stream of
tiny particles; Huygens and later Young pictured a spreading wave.
Young seemed to settle it in 1801: shine light through two narrow slits and it produces a pattern of
bright and dark interference fringes — something only waves can do. Wave, case
closed.
Except that a century later the photoelectric
effect refused to obey. Light knocking electrons out of a metal behaves as if it arrives
in tiny lumps of energy — photons — each one a particle. So which is it? The strange,
deep answer of modern physics is: both. Light is neither purely a wave nor purely a
stream of particles. It is something that shows a wave face in one experiment and a
particle face in another. We call this wave–particle duality.
The two faces of light
Line up the evidence and neither side wins outright — each experiment reveals a different face of the
same thing.
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The wave face. Light interferes
and diffracts. Two overlapping beams add crest-to-crest and cancel crest-to-trough,
producing fringes; light spreads and bends around edges and through gaps. Only a wave, with a
\text{wavelength }\lambda, can do this.
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The particle face. In the photoelectric effect, the energy delivered comes in
discrete photons, each carrying E = hf. Dim blue light ejects electrons
while bright red light ejects none — impossible for a smooth wave, natural for particles arriving
one lump at a time.
Here is the key idea to hold onto: light does not switch from wave to particle. It is a
single thing whose full nature is richer than either everyday picture, and which of the two faces you
see depends only on the question your experiment asks.
De Broglie's bold leap: matter has waves too
In 1924 a young French physicist, Louis de Broglie, asked a question so simple it is almost cheeky.
If light — long thought a pure wave — can behave like a particle, then perhaps things we have always
thought of as particles, such as electrons, can behave like waves.
Nature, he reasoned, ought to be symmetric.
He went further and said how long the wave should be. Borrowing the photon relation, he
proposed that any particle with momentum p = mv has an associated
wavelength — the de Broglie wavelength:
\lambda = \dfrac{h}{p} = \dfrac{h}{mv}.
Here h = 6.63\times10^{-34}\ \text{J s} is Planck's constant — the same
tiny number that governs photons. The relation ties a wave property, \lambda,
to a particle property, p, in one stroke. And notice its shape:
\lambda and p are inversely
proportional. Push the momentum up and the wavelength shrinks; let the momentum fall and the
wavelength grows.
-
Every moving particle has an associated wavelength
\lambda = \dfrac{h}{p} = \dfrac{h}{mv}, where
p = mv is its momentum and
h = 6.63\times10^{-34}\ \text{J s} is Planck's constant.
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Wavelength and momentum are inversely proportional: a bigger momentum means a
shorter wavelength, and a smaller momentum a longer one.
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It applies to everything with momentum — electrons, atoms, cricket balls, you —
not just to light.
Worked examples: sizing a matter wave
Example 1 — an electron. An electron (mass
m_e = 9.11\times10^{-31}\ \text{kg}) moves at
v = 2.0\times10^{6}\ \text{m s}^{-1}. Find its de Broglie wavelength.
-
Momentum: p = m_e v = (9.11\times10^{-31})(2.0\times10^{6}) = 1.82\times10^{-24}\ \text{kg m s}^{-1}.
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Wavelength: \lambda = \dfrac{h}{p} = \dfrac{6.63\times10^{-34}}{1.82\times10^{-24}} = 3.6\times10^{-10}\ \text{m}.
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That is about 0.36\ \text{nm} — roughly the spacing between atoms in a
crystal. A wave this size will diffract off the rows of atoms, which is exactly
what we see.
Example 2 — a cricket ball. A ball of mass
m = 0.16\ \text{kg} is bowled at
v = 40\ \text{m s}^{-1}. What is its de Broglie wavelength?
- Momentum: p = mv = 0.16 \times 40 = 6.4\ \text{kg m s}^{-1}.
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Wavelength: \lambda = \dfrac{6.63\times10^{-34}}{6.4} \approx 1.0\times10^{-34}\ \text{m}.
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This is unimaginably small — about
10^{24} times smaller than the width of a single proton. No experiment
could ever detect a wave that short, which is why a cricket ball simply looks like a particle.
Example 3 — working backwards. An electron is measured to have a de Broglie
wavelength of \lambda = 1.0\times10^{-10}\ \text{m}. Find its momentum and
its speed.
-
Rearrange for momentum:
p = \dfrac{h}{\lambda} = \dfrac{6.63\times10^{-34}}{1.0\times10^{-10}} = 6.63\times10^{-24}\ \text{kg m s}^{-1}.
-
Then speed from p = m_e v:
v = \dfrac{p}{m_e} = \dfrac{6.63\times10^{-24}}{9.11\times10^{-31}} \approx 7.3\times10^{6}\ \text{m s}^{-1}.
Notice the pattern across all three: only a very light particle moving at a modest speed gets a
wavelength big enough to matter. That single fact is the whole reason we see wave behaviour in
electrons but never in everyday objects.
Watch the wavelength shrink
Below is the curve \lambda = \dfrac{h}{p} — a smooth inverse
drop. The horizontal axis is momentum, the vertical axis is the de Broglie wavelength. Drag the
slider to change the electron's momentum and watch the point slide along the curve: as
p grows the wavelength falls away, and as p
shrinks it climbs. Because the axes are in tiny units
(10^{-24} for p,
10^{-10}\ \text{m} for \lambda), this whole
readable curve lives entirely in the world of the electron. An everyday object would sit far, far off
the right-hand edge, its wavelength crushed to nothing.
A graph of de Broglie wavelength against momentum, an inverse curve falling from top-left to
bottom-right. A marker slides along it as you change the momentum slider, and a readout shows the
matching momentum, wavelength, and the corresponding electron speed.
Electron diffraction: the proof
De Broglie's idea was beautiful, but physics needs evidence. It came within a few years. Fire a beam
of electrons through a very thin slice of graphite (a crystal, so its atoms sit in neat, evenly spaced
rows) and let them land on a screen. If electrons were only particles you would expect a single bright
spot straight ahead. Instead the screen shows a pattern of concentric rings — bright
and dark, exactly like the diffraction pattern a wave makes when it passes through a regular
grating.
There is no way to explain rings with particles alone: only a wave can diffract. The
rows of atoms act as the "slits," and their spacing is comparable to the electron's de Broglie
wavelength (recall Example 1: about 10^{-10}\ \text{m}), so the wave nature
shows up clearly. This experiment is the direct confirmation that matter has a wavelength.
The relation even predicts how the pattern should change. Speed the electrons up — increase their
momentum p — and \lambda = h/p falls. A shorter
wavelength diffracts less, so the rings squeeze inwards and the whole pattern gets
smaller. Slow the electrons down and the rings spread out. Watching the rings shrink
as you raise the accelerating voltage is the de Broglie formula made visible.
Why big things stay "just particles"
If everything has a de Broglie wavelength, why do we only ever see the effect for electrons and other
tiny particles? The answer is baked into \lambda = h/mv. Planck's constant
h is fantastically small, so the wavelength is only appreciable when the
momentum mv is also fantastically small.
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An electron has a mass of about 10^{-30}\ \text{kg}. Its
momentum is tiny, so \lambda comes out around
10^{-10}\ \text{m} — big enough to diffract off atoms. We see the wave.
-
A cricket ball has a mass around 0.16\ \text{kg}. Its
momentum is colossal by comparison, so \lambda \approx 10^{-34}\ \text{m}
— trillions of times smaller than an atom. There is no gap in the universe narrow enough to make
it diffract. We only ever see the particle.
This tiny wavelength is not just a curiosity — it is a tool. An electron microscope
deliberately uses fast electrons precisely because their de Broglie wavelength is thousands of times
shorter than that of visible light. The smallest detail any microscope can resolve is set by its
wavelength, so short-wavelength electrons can image things far too small for light to distinguish —
individual viruses, and even rows of atoms.
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Everything has a de Broglie wavelength — we just can't detect most of them. A
bus, a tennis ball, you walking to school: each has a real \lambda = h/p.
It is simply so absurdly tiny (because everyday momenta are enormous) that no experiment could ever
reveal it. "No wave effects" means "immeasurably small," not "exactly zero."
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Bigger momentum means a SHORTER wavelength, not a longer one. The relation is
inverse: \lambda \propto 1/p. A common slip is to think
speeding a particle up "stretches" its wave — it does the opposite. Faster electrons diffract
less, and their rings shrink.
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Duality does not mean flipping between two modes. Light and matter are not a wave
that "turns into" a particle when you look, nor a particle that "turns into" a wave. They are a
single kind of thing that is both at once; different experiments simply reveal different
faces of it.
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Use momentum p = mv, not just speed. The wavelength
depends on momentum. Two particles at the same speed but different masses have different
wavelengths, because the heavier one has more momentum.
Here is the experiment that unsettles even physicists. Take the electron diffraction idea and turn the
beam down so low that only a single electron crosses the apparatus at once, then fire
them one by one at a double slit. Each electron lands as a single dot on the screen — clearly a
particle arriving at one place. But let thousands accumulate, dot after lonely dot, and the pattern
that builds up is… interference fringes.
Every electron, on its own, somehow "knows" about both slits and lands where the wave says it should
be likely to. The particle you can count and the wave that guides where it goes are the same object.
Richard Feynman called this the one experiment holding "the heart of quantum mechanics" — the whole
mystery of wave–particle duality in a single, stubborn picture.