Diffraction
Shout from one room and a friend in the next room hears you plainly, even though a solid wall
stands between you and the only opening is a doorway off to one side. The sound does not travel in
a tidy straight beam through the gap and stop dead at the edges of it — it bends round the
edges and floods the whole next room. Now take a laser pointer, a beautifully collimated
pencil of light, and send it through a slit scratched a fraction of a millimetre wide. On the far
wall you do not get a thin bright line the shape of the slit. You get a broad smear of light,
brightest in the middle and fading through a series of dark and bright bands out to the sides. The
narrower you make the slit, the wider the smear spreads.
Both of these are the same phenomenon: diffraction — the bending and spreading of
a wave as it passes an aperture or an edge. It is not a minor optical blemish. Diffraction is the
hard limit on the sharpness of every telescope, microscope and camera ever built; it is the working
principle of the spectrometers that tell us what stars are made of; and it is one of the cleanest
pieces of evidence that light is a wave at all. This page teaches diffraction as a first-year
physicist meets it: the qualitative picture, then the quantitative single slit, then the diffraction
grating — and the sign trap that snares almost everyone who studies both at once.
What diffraction is, and when it matters
Treat every point on a wavefront as a little source of its own outgoing wavelets — that is
Huygens' principle. When an unbroken plane wave rolls forward, those countless
wavelets add up along the front and cancel everywhere else, so the wave marches on in a straight
line. But put a barrier with a gap in it, and you slice out only a short strip of wavefront. The
wavelets from that strip have no neighbours out to the sides to cancel against, so the wave
curls into the geometric shadow and spreads beyond the gap.
How much it spreads is governed by a single comparison — the aperture width
a against the wavelength \lambda:
-
Aperture much wider than the wavelength (a \gg \lambda):
the beam passes almost straight through with only a little fraying at the rims. A window is
millions of wavelengths of light wide, so daylight through it casts a crisp-edged patch — barely
any diffraction.
-
Aperture comparable to the wavelength (a \approx \lambda):
the spreading is dramatic, fanning out through a wide arc as though the gap were a single fresh
point source.
This one comparison explains the opening puzzle. Everyday sound has a wavelength of order a metre —
about the width of a doorway — so it diffracts strongly and fills the next room. Visible light has a
wavelength under a thousandth of a millimetre, so against a doorway a/\lambda
is enormous, diffraction is negligible, and light travels on as sharp rays. To make light spread the
way sound does, you must shrink the aperture down toward the wavelength itself — which is exactly
what a diffraction slit does.
The single slit: where the dark fringes come from
Send monochromatic plane waves (one wavelength \lambda) straight at a
single slit of width a and collect the light far away, at an angle
\theta from the straight-through direction. By Huygens, imagine the open
slit divided into a great many tiny strips, each radiating a wavelet. The pattern on the screen is
the sum — the interference —
of all of them, and whether a given direction is bright or dark depends only on the
path differences between those strips.
Here is the elegant argument for the dark fringes. The wavelet from the very top of
the slit and the wavelet from the very bottom differ in path length by
a\sin\theta. Now split the slit into two equal halves and pair up each
strip in the top half with the strip a distance a/2 below it in the
bottom half. Every such pair differs in path by (a/2)\sin\theta. If that
half-slit path difference is exactly half a wavelength, every pair cancels — the whole slit
goes dark. That gives the first minimum:
\frac{a}{2}\sin\theta = \frac{\lambda}{2} \quad\Longrightarrow\quad a\sin\theta = \lambda.
Splitting into four strips, six strips, and so on repeats the trick and yields a dark fringe
whenever
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Dark fringes (minima) fall at angles satisfying
a\sin\theta = m\lambda, for m = \pm 1, \pm 2, \pm 3, \dots
-
The sign trap: m = 0 is excluded. It does
not give a minimum — it is the direction straight ahead, the bright
central maximum. The integers m count outward dark
fringes on either side.
-
The central maximum is twice as wide as the side fringes: it runs from the
m = -1 minimum to the m = +1 minimum, a
span of 2\lambda/a in \sin\theta, while
each side fringe spans only \lambda/a.
Notice the shape of the result: the first minimum sits at \sin\theta = \lambda/a,
so a narrower slit (smaller a) throws the fringes out to
larger angles — the pattern spreads. That is diffraction's signature written into
the algebra: squeeze the aperture toward \lambda and the light fans wide.
The full intensity pattern
The minima locate the dark bands, but adding up all the wavelets (a neat exercise with phasors)
gives the complete brightness curve. Writing the half-phase across the slit as
\beta = \frac{\pi a \sin\theta}{\lambda},
the intensity at angle \theta is
-
I(\theta) = I_0 \left(\dfrac{\sin\beta}{\beta}\right)^2, with
\beta = \pi a \sin\theta/\lambda and I_0 the
central peak intensity.
-
The bracket is the sinc function. At \beta \to 0 it
tends to 1 (the central maximum), not to 0/0
— the tidy limit \sin\beta/\beta \to 1.
-
Zeros of \sin\beta (at \beta = m\pi) are the
minima — which reproduces a\sin\theta = m\lambda exactly.
Drag the slider below to change the slit width, measured in wavelengths
(a/\lambda), and watch the pattern breathe. A wider slit
pulls the central peak into a tight, tall spike with many faint side lobes crowded near the middle;
a narrower slit flings the whole pattern wide open. The side lobes are strikingly
faint — the first is only about 4.5\% of the central peak — which is why
the middle of a single-slit pattern so dominates the eye.
Worked examples — the single slit
Example 1 — angle of the first minimum. Red laser light,
\lambda = 633\ \text{nm}, passes through a slit of width
a = 0.0200\ \text{mm} = 2.00\times10^{-5}\ \text{m}. Where is the first
dark fringe? Use a\sin\theta = m\lambda with m = 1:
\sin\theta = \frac{m\lambda}{a} = \frac{1 \times 633\times10^{-9}}{2.00\times10^{-5}} = 0.0317, \qquad \theta = \sin^{-1}(0.0317) = 1.81^\circ.
The central bright band therefore stretches from -1.81^\circ to
+1.81^\circ — an angular width of 3.6^\circ,
twice the half-angle, just as promised.
Example 2 — width on a screen. That pattern falls on a wall
L = 3.0\ \text{m} away. For small angles
\sin\theta \approx \tan\theta = y/L, so the half-width of the central
maximum is
y = L\tan\theta \approx L\,\frac{\lambda}{a} = 3.0 \times \frac{633\times10^{-9}}{2.00\times10^{-5}} = 0.095\ \text{m} \approx 9.5\ \text{cm}.
The full central band is about 19\ \text{cm} wide — a broad glow, from a
slit narrower than a hair.
Example 3 — squeeze the slit. Halve the slit to
a = 1.00\times10^{-5}\ \text{m} with the same light. The first minimum
moves to \sin\theta = \lambda/a = 0.0633,
\theta = 3.63^\circ — double the angle. Narrowing the aperture
widens the spread, exactly the inverse relationship \sin\theta \propto 1/a
built into a\sin\theta = m\lambda.
From one slit to thousands: the diffraction grating
A diffraction grating replaces the single slit with a great many identical,
equally spaced slits — a plate ruled with hundreds or thousands of fine parallel lines per
millimetre, each clear strip a slit. Call the centre-to-centre spacing between neighbouring slits
d, the grating spacing (with N
lines per metre, d = 1/N).
Look at light leaving the grating at angle \theta. Each slit's wavelet
travels an extra d\sin\theta compared with its neighbour. For all those
thousands of wavelets to arrive in step and build an intense beam, that extra path
must be a whole number of wavelengths. Anything else and the marching phase differences,
summed over thousands of slits, cancel to nothing. Hence the principal maxima:
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Bright principal maxima occur at angles with
d\sin\theta = m\lambda, for m = 0, \pm 1, \pm 2, \dots
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m is the order. Here m = 0
is included: it is the undeviated central beam, bright for every wavelength.
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Because \sin\theta \le 1, there is a highest order:
m_\text{max} = \lfloor d/\lambda \rfloor. Orders beyond that would need
\sin\theta > 1 and simply do not exist.
The many slits do two things a single slit cannot. First, they make each maximum
needle-sharp: with N slits contributing, the bright
orders narrow roughly as 1/N, so a grating of ten thousand slits gives
pinpoint spots against wide dark gaps. Second, because the angle of each order depends on
\lambda, the grating splits white light into a spectrum,
throwing each colour to its own angle — the foundation of spectroscopy.
The sharper the maxima, the finer the wavelengths a grating can tell apart — its
resolving power. Qualitatively, two nearby wavelengths are resolvable when their
peaks are narrower than their separation; since peak width falls as 1/N,
more illuminated slits means finer resolution. In symbols the resolving power is
\lambda/\Delta\lambda = mN — it improves with both the order
m and the number of slits N the beam covers.
This is precisely why a grating, not a single slit, is the instrument of choice for measuring the
wavelengths in starlight.
Worked examples — the grating
Example 1 — spacing from lines per millimetre. A grating has
500 lines per millimetre. That is
N = 5.00\times10^{5} lines per metre, so
d = \frac{1}{N} = \frac{1}{5.00\times10^{5}} = 2.00\times10^{-6}\ \text{m} = 2000\ \text{nm}.
Example 2 — angles of the orders. Green light,
\lambda = 500\ \text{nm}, hits that grating. First order
(m = 1):
\sin\theta = \frac{m\lambda}{d} = \frac{1 \times 500}{2000} = 0.250, \qquad \theta = 14.5^\circ.
Second order sits at \sin\theta = 0.500,
\theta = 30.0^\circ; third order at
\sin\theta = 0.750, \theta = 48.6^\circ —
higher orders always at wider angles.
Example 3 — how many orders? Same grating, red light
\lambda = 650\ \text{nm}. Set \sin\theta = 1:
m_\text{max} = \left\lfloor \frac{d}{\lambda} \right\rfloor = \left\lfloor \frac{2000}{650} \right\rfloor = \lfloor 3.08 \rfloor = 3.
Orders 0, \pm 1, \pm 2, \pm 3 appear — seven bright spots. The would-be
"m = 3.08" is not an arithmetic slip; it just means the fourth order has
run off past \sin\theta = 1 and vanished.
Example 4 — measuring a wavelength. This is what gratings are for. Light
through a grating with d = 1.67\times10^{-6}\ \text{m} (a
600 lines/mm grating) gives a first-order maximum at
\theta = 21.1^\circ:
\lambda = \frac{d\sin\theta}{m} = \frac{1.67\times10^{-6}\times\sin 21.1^\circ}{1} = 1.67\times10^{-6}\times 0.360 = 601\ \text{nm}.
One angle read off a rotating table pins the wavelength to a few nanometres — orange light.
Single slit versus grating — read the equation carefully
The two headline equations look almost identical, and that is the whole danger. They describe
opposite things:
-
Single slit: a\sin\theta = m\lambda locates the
dark fringes (minima), with m = \pm 1, \pm 2, \dots
and m = 0 pointedly excluded — a is the
width of the one slit.
-
Grating: d\sin\theta = m\lambda locates the
bright maxima, with m = 0, \pm 1, \pm 2, \dots and
m = 0 firmly included — d is the
separation between neighbouring slits.
Same shape, opposite meaning. The single-slit condition kills the light; the grating condition
lights it up. And the two effects coexist: in a real grating each slit has a finite width
a, so the single-slit envelope (a) modulates
the brightness of the grating's sharp orders (d) — occasionally a
grating order lands right on a single-slit minimum and is snuffed out, a "missing order".
This is the trap that costs the most marks on this topic. Both patterns give you an equation of the
form (\text{length})\times\sin\theta = m\lambda — but what that equation
locates flips completely:
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For a single slit, a\sin\theta = m\lambda gives the
MINIMA — the dark bands. The bright centre is at
m = 0, which the formula deliberately leaves out.
-
For a grating, d\sin\theta = m\lambda gives the
MAXIMA — the bright orders. Here m = 0 is the
brightest one, straight ahead.
Before you plug numbers in, ask two things: am I finding bright or dark? and is the
length in front of \sin\theta the width of one slit
(a) or the gap between slits (d)? Get
those straight and the sign convention on m (excluded for single-slit
minima, included for grating maxima) takes care of itself.
Because diffraction sets a floor on sharpness that no amount of polishing can beat. A telescope's
circular aperture of diameter D diffracts incoming light into a tiny
blur — the Airy disc — whose angular radius is
\theta \approx 1.22\,\lambda/D (the circular cousin of the single slit's
\lambda/a, with a factor 1.22 from the round
shape). Two point sources closer together than this cannot be told apart, no matter how perfect the
optics: this is the Rayleigh criterion for resolution.
For the Hubble Space Telescope, D = 2.4\ \text{m} and
\lambda \approx 550\ \text{nm} give
\theta \approx 2.8\times10^{-7}\ \text{rad} — about a tenth of an
arcsecond. From a low orbit 300\ \text{km} up that blur is roughly
8\ \text{cm} across on the ground: enough to see a car, nowhere near
enough to read its plate. Want finer detail? The only cures are a bigger aperture or a
shorter wavelength — which is exactly why radio telescopes must be gigantic (long
\lambda) and why electron microscopes, using electrons of picometre
wavelength, out-resolve any light microscope by thousands of times. Diffraction is not a flaw in
our instruments; it is a law about waves.