The Kinetic Theory of Gases
By now you can use a gas: squeeze it and the pressure climbs, warm it and it swells or
pushes harder, and the whole lot is tied together by
the ideal gas equation,
pV = NkT. But every one of those rules was discovered by
measuring gases from the outside. None of them explains why a gas
behaves that way. Where does the pressure actually come from? What is temperature, deep
down?
The kinetic theory of gases answers those questions by taking one bold idea
completely seriously: a gas is nothing but a vast swarm of tiny molecules in ceaseless,
random motion, obeying ordinary Newtonian mechanics — bouncing off the walls, bouncing
off each other, flying in straight lines in between. Astonishingly, if you apply
Newton's laws to that
swarm and average over its billions of members, the entire behaviour of the gas —
pV, temperature, all of it — drops out of the mathematics.
This page is that derivation: bulk gas behaviour, built from moving molecules.
The rules of the game: the assumptions
To turn "a box of bouncing molecules" into equations we need a clean, idealised model. The
kinetic theory of an ideal gas rests on a short list of assumptions — each one a
deliberate simplification that makes the maths tractable while staying close to how a real dilute
gas actually behaves:
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A gas contains a very large number of identical molecules, each of mass
m, moving in random directions with a spread of
speeds. "Large" means large enough — \sim 10^{23} — that we can talk
about statistical averages with confidence.
-
The molecules have negligible volume compared with the volume of the
container. They are treated as point particles: the gas is almost entirely
empty space.
-
There are no intermolecular forces between molecules, except during the
instant of a collision. Between collisions each molecule travels in a straight line at constant
velocity, feeling nothing from its neighbours (we also ignore gravity over the box).
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All collisions — molecule with wall, and molecule with molecule — are
perfectly elastic: kinetic energy is conserved, so the molecules never slow
down and settle.
-
The duration of a collision is negligible compared with the time a molecule
spends flying freely between collisions.
These are exactly the conditions under which a real gas is well described by
pV = NkT — a hot, dilute gas well away from the point where it would
condense into a liquid. Keep them in mind: every step below leans on one of them.
Where the pressure comes from
Picture the gas in a cubical box of side L, and follow a
single molecule as it heads straight at the right-hand wall with an
x-velocity u. Pressure is going to be the
blur of countless such molecules drumming on that wall — so let's find the push from one, then
add them up.
Step 1 — momentum change in one bounce. The collision is elastic, so the
molecule rebounds with its x-velocity exactly reversed, from
+u to -u. Its change of momentum is
\Delta p = m u - (-m u) = 2 m u.
Step 2 — how often it hits. After bouncing it must cross to the far wall and
come back — a round trip of 2L — before it strikes this wall again. At
speed u that takes a time
\Delta t = \dfrac{2L}{u}.
Step 3 — the average force from one molecule. By
Newton's second law,
force is the rate of change of momentum, so this molecule's average push on the wall is
F = \dfrac{\Delta p}{\Delta t} = \dfrac{2mu}{2L/u} = \dfrac{m u^2}{L}.
Step 4 — add up all the molecules. Every molecule contributes its own
m u_i^2 / L, so the total force on the wall is
F = \dfrac{m}{L}\left(u_1^2 + u_2^2 + \cdots + u_N^2\right). Writing the
mean of the squared x-speeds as
\overline{u^2}, this is
F = \dfrac{Nm\,\overline{u^2}}{L}.
Step 5 — three directions, so bring in \overline{c^2}.
A molecule's true speed c has components in all three directions,
c^2 = u^2 + v^2 + w^2. Motion is random, so on average no direction is
special: \overline{u^2} = \overline{v^2} = \overline{w^2}, and
therefore \overline{u^2} = \tfrac13\,\overline{c^2}, where
\overline{c^2} is the mean-square speed.
Step 6 — divide force by area to get pressure. The wall has area
A = L^2 and the box has volume V = L^3.
Putting \overline{u^2} = \tfrac13\overline{c^2} into the force and
dividing by A:
p = \dfrac{F}{A} = \dfrac{Nm\,\overline{u^2}}{L^3} = \dfrac{1}{3}\,\dfrac{Nm\,\overline{c^2}}{V},
which rearranges into the central result of the whole theory:
pV = \tfrac13 N m \,\overline{c^2}.
Look at what just happened. We fed in nothing but Newton's laws and a box of bouncing points —
and out came a relationship between the bulk pressure and volume of a gas and the
microscopic mass, number and speed of its molecules. Everything else follows from here.
Temperature is molecular kinetic energy
We now have two expressions for the very same quantity pV:
the one measured from the outside, and the one derived from the molecules inside.
pV = N k T \qquad\text{and}\qquad pV = \tfrac13 N m \,\overline{c^2}.
Set them equal — they describe the same gas — and the number of molecules
N cancels straight off both sides:
\tfrac13 N m \,\overline{c^2} = N k T \;\;\Longrightarrow\;\; \tfrac13 m \,\overline{c^2} = k T.
Multiply through by \tfrac32 and the left-hand side becomes the
average kinetic energy of a molecule, \tfrac12 m \overline{c^2}:
\tfrac12 m \,\overline{c^2} = \tfrac32 k T.
This is one of the most important sentences in all of thermal physics. The left-hand side is the
mean translational kinetic energy of a single molecule; the right-hand side is
just a constant times the absolute temperature. So temperature is not some
separate substance or fluid — the absolute (kelvin) temperature of a gas is a direct
measure of the average kinetic energy of its molecules. Double the kelvin temperature
and you have doubled the mean molecular KE. Notice too that the mass has vanished: at a given
temperature every gas, heavy or light, has the same mean translational KE per molecule.
And it explains absolute zero at last. As
T \to 0\,\text{K}, the right-hand side goes to zero, so
\tfrac12 m \overline{c^2} \to 0: molecular motion falls to its
absolute minimum. You cannot cool further, because there is no kinetic energy left to remove.
For an ideal gas of N molecules, each of mass
m, with mean-square speed \overline{c^2}:
-
Pressure arises from molecular collisions with the walls, giving the kinetic
theory equation pV = \tfrac13 N m \,\overline{c^2}.
-
Temperature is a measure of mean molecular kinetic energy: combining with
pV = NkT gives
\tfrac12 m \,\overline{c^2} = \tfrac32 k T, so the mean
translational KE per molecule is directly proportional to the absolute temperature.
Startlingly fast. The air around you sits at about 293\,\text{K}, and
a nitrogen molecule (mass 4.7\times10^{-26}\,\text{kg}) at that
temperature has a root-mean-square speed of very nearly
500\ \text{m s}^{-1} — roughly the speed of a rifle bullet, or one
and a half times the speed of sound. Every molecule of the air you are breathing is hurtling
about at that pace, changing direction billions of times a second as it smashes into its
neighbours.
The same equation explains why the Earth keeps its atmosphere but the Moon has none, and why
helium balloons are a slightly futile purchase. Since
\tfrac12 m \overline{c^2} = \tfrac32 kT, a lighter molecule
moves faster at the same temperature. Light, nimble helium and
hydrogen molecules zip along so quickly that many exceed Earth's escape velocity and trickle
away into space over millions of years — which is why free helium is rare in our atmosphere and
why your helium balloon deflates as the tiny atoms squeeze out through the rubber. Heavier
nitrogen and oxygen are too sluggish to escape, so they stay — and we get to breathe.
The root-mean-square speed
The mean-square speed \overline{c^2} is an average of squares,
so its units are \text{m}^2\,\text{s}^{-2} — not a speed at all. To get
back to something measured in \text{m s}^{-1} we take the square root,
and the result is the root-mean-square speed:
c_{\text{rms}} = \sqrt{\overline{c^2}}.
It is a genuine three-step recipe, and the order matters: take every molecule's speed,
square it, take the mean of all those squares, then take the
square root — root of the mean of the squares. It is the natural "typical" speed
to quote, because it is the one tied directly to the kinetic energy.
Rearranging the temperature result \tfrac12 m \overline{c^2} = \tfrac32 kT
gives \overline{c^2} = \dfrac{3kT}{m}, and taking the root:
c_{\text{rms}} = \sqrt{\overline{c^2}} = \sqrt{\dfrac{3kT}{m}}.
Two features are worth burning in. First, c_{\text{rms}} \propto \sqrt{T}:
to double the rms speed you must quadruple the absolute temperature. Second,
c_{\text{rms}} \propto 1/\sqrt{m}: at a given temperature, lighter
molecules are faster — exactly the fact behind the escaping helium.
Worked examples
Example 1 — rms speed from temperature. Find the root-mean-square speed of
nitrogen molecules (mass m = 4.7\times10^{-26}\,\text{kg}) in air at
27\,^\circ\text{C}. Take
k = 1.38\times10^{-23}\,\text{J K}^{-1}.
Step 1 — temperature in kelvin.
T = 27 + 273 = 300\ \text{K}.
Step 2 — use c_{\text{rms}} = \sqrt{3kT/m}.
c_{\text{rms}} = \sqrt{\dfrac{3 \times 1.38\times10^{-23} \times 300}{4.7\times10^{-26}}} = \sqrt{2.64\times10^{5}} \approx 514\ \text{m s}^{-1}.
Around 500\ \text{m s}^{-1} — faster than the speed of sound, just as
promised.
Example 2 — mean kinetic energy from temperature. What is the mean translational
kinetic energy of any ideal-gas molecule at 300\ \text{K}?
This one needs no mass at all — it depends only on temperature, through
\tfrac12 m \overline{c^2} = \tfrac32 kT:
\overline{E_k} = \tfrac32 k T = \tfrac32 \times 1.38\times10^{-23} \times 300 = 6.21\times10^{-21}\ \text{J}.
A helium atom and a heavy carbon-dioxide molecule side by side at
300\ \text{K} carry the same mean KE — the helium simply
reaches it by moving much faster.
Example 3 — pressure straight from the kinetic theory equation. A container of
volume V = 0.025\ \text{m}^3 holds
N = 1.0\times10^{24} molecules, each of mass
m = 5.0\times10^{-26}\,\text{kg}, with a mean-square speed
\overline{c^2} = 3.0\times10^{5}\ \text{m}^2\,\text{s}^{-2}. Find the
pressure.
Step 1 — write pV = \tfrac13 N m \overline{c^2} and solve for
p.
p = \dfrac{N m \,\overline{c^2}}{3V}.
Step 2 — substitute.
p = \dfrac{(1.0\times10^{24})(5.0\times10^{-26})(3.0\times10^{5})}{3 \times 0.025} = \dfrac{1.5\times10^{4}}{0.075} = 2.0\times10^{5}\ \text{Pa}.
That is about 200\ \text{kPa} — roughly twice atmospheric pressure —
obtained without ever putting a gauge on the container, purely from the mechanics of the swarm
inside.
See the swarm
Here is the box of molecules the whole theory is about. Each molecule carries a
velocity arrow whose length is its speed. Drag the
temperature slider and watch the arrows grow: raising the temperature raises the
mean molecular kinetic energy, so the molecules move faster (the arrows lengthen as
\sqrt{T}, since c_{\text{rms}} \propto \sqrt{T}).
The Mean KE bar on the right rises in exact proportion to the absolute
temperature — that is what temperature means. Drag the number slider and
more molecules join the swarm; notice the mean KE and the rms speed don't change when you
add molecules, because temperature is an average per molecule, not a total.
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Temperature measures the AVERAGE kinetic energy per molecule — not the total.
\tfrac12 m \overline{c^2} = \tfrac32 kT is a statement about a
single molecule's mean KE. Two gases at the same temperature have the same mean KE per
molecule even if one holds far more molecules (and so far more total energy). Temperature is a
per-molecule average; it does not tell you how much gas there is.
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It is the KINETIC energy, and only the translational part. The result is about
the energy of molecules flying about. It says nothing about potential energy in bonds
(an ideal gas has none), which is exactly why an ideal gas is a special, simple case of
internal energy.
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c_{\text{rms}} is the root-MEAN-SQUARE speed, not the plain
average speed. You square first, then average, then square-root. Because squaring
weights the fast molecules more heavily, c_{\text{rms}} is always a
little larger than the simple mean speed — they are not the same number.
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The model assumes point particles with no forces between them. That is what
makes it an ideal gas. Real gases deviate — most noticeably when cold or highly
compressed, when the molecules' own volume and their mutual attractions can no longer be
ignored.