Kinetic Energy
Roll a bowling ball down the lane and it flattens the pins. Let the wind push a turbine and it
lights a town. Miss the brakes and a car crumples a lamp-post like paper. In every case
something moving does the damage — the pins, the turbine and the lamp-post all
felt the same thing: the energy carried by a moving object.
That energy of motion is called kinetic energy (from the Greek kinesis,
"movement"). Anything that is moving has it; the instant something stops, its kinetic energy is
gone (it has been passed on to whatever it hit, or drained away as heat and sound). The faster a
thing goes, and the more mass it has, the more kinetic energy it carries — and, as we're about to
see, speed matters far more than you'd guess.
The formula
Kinetic energy depends on just two things: how much mass the object has
(m, in kilograms) and how fast it is going
(v, its speed in metres per second). They combine like this:
E_k = \tfrac12 m v^2
The answer comes out in joules (J) — the same unit we use for every kind of
energy, so kinetic energy can be swapped for
other stores and for the
work done by a force. Reading the formula
piece by piece:
- m — the mass in kg. Double the mass and you double the energy.
- v — the speed in m/s. But v is squared, so its effect is far stronger (next card).
- \tfrac12 — a fixed one-half that always sits out front.
An object of mass m moving at speed v stores
kinetic energy
E_k = \tfrac12 m v^2,
- E_k in joules (J),
- m in kilograms (kg),
- v in metres per second (m/s).
The squared speed changes everything
Here is the single most important fact on this page. Because it is v^2
and not just v, doubling the speed does not double the kinetic
energy — it quadruples it. Squaring means the speed gets multiplied by itself, so twice
the speed gives 2^2 = 4 times the energy.
Take one object and leave its mass alone, so only the speed changes. Watch what its kinetic energy does:
- Speed \times 1 → energy \times 1
- Speed \times 2 → energy \times 4 (2^2)
- Speed \times 3 → energy \times 9 (3^2)
- Speed \times 4 → energy \times 16 (4^2)
This one line of maths is why speed limits exist. A car at 40 mph carries four times the
wrecking energy it had at 20 mph — not twice — which is why a small rise in speed makes a crash so
much more violent, and why the braking distance grows so alarmingly (the brakes have four times as
much energy to soak up).
Worked examples
1. A family car. Mass m = 1000\ \text{kg}, speed
v = 20\ \text{m/s} (about 45 mph).
E_k = \tfrac12 m v^2 = \tfrac12 \times 1000 \times 20^2 = \tfrac12 \times 1000 \times 400 = 200\,000\ \text{J} = 200\ \text{kJ}.
2. The same car, twice as fast. Now
v = 40\ \text{m/s}. Nothing else changed.
E_k = \tfrac12 \times 1000 \times 40^2 = \tfrac12 \times 1000 \times 1600 = 800\,000\ \text{J} = 800\ \text{kJ}.
Doubling the speed from 20 to 40 m/s took the energy from 200 kJ to 800 kJ — exactly
four times as much, just as the squaring promised.
3. A kicked football. Mass m = 0.4\ \text{kg}, speed
v = 25\ \text{m/s}.
E_k = \tfrac12 \times 0.4 \times 25^2 = \tfrac12 \times 0.4 \times 625 = 125\ \text{J}.
4. Rearranging to find the speed. A 2\ \text{kg} ball
carries E_k = 400\ \text{J}. How fast is it going? Start from
E_k = \tfrac12 m v^2 and unwrap v: multiply
both sides by 2, divide by m, then square-root.
v = \sqrt{\dfrac{2 E_k}{m}} = \sqrt{\dfrac{2 \times 400}{2}} = \sqrt{400} = 20\ \text{m/s}.
Mass matters too: a lorry versus a car
Speed is squared, but mass counts as well — straight, not squared. Put a heavy lorry and a light
car side by side at the same speed and the lorry's extra mass alone gives it a huge
kinetic-energy advantage.
A loaded lorry (m = 20\,000\ \text{kg}) at
v = 20\ \text{m/s}:
E_k = \tfrac12 \times 20\,000 \times 20^2 = 4\,000\,000\ \text{J} = 4\ \text{MJ}.
That is 20 times the 200 kJ of our 1000 kg car at the same speed — because it has
20 times the mass. A slow-moving lorry is anything but harmless. And a fast marble is not nothing
either: a tiny mass at a huge speed (a bullet, a hailstone, space debris) can carry plenty of
energy, because that squared speed does the heavy lifting. To have a lot of kinetic energy you need
either a big mass or a big speed — and a big speed is worth much more.
Three traps catch almost everyone with E_k = \tfrac12 m v^2:
-
Speed is squared, not doubled. If the speed triples, the kinetic energy does
not triple — it goes up 3^2 = 9 times. Always square the
speed before multiplying, never after.
-
Only the speed is squared — not the mass, and not the \tfrac12.
It is \tfrac12 m v^2, meaning \tfrac12 \times m \times (v \times v),
not (\tfrac12 m v)^2.
-
You need mass and speed. A parked lorry has enormous mass but zero
speed, so E_k = 0. A stationary object — however heavy — carries no
kinetic energy at all. Motion is what makes it kinetic.
Try it: watch the curve steepen
Below is a graph of kinetic energy against speed for a car. Drag the speed slider
and the marker climbs the curve; the readout works out E_k = \tfrac12 m v^2
live. Notice the shape — it is not a straight line but a curve that steepens,
because of the v^2. Go from 10 to 20 m/s and the energy roughly
quadruples; the same jump higher up adds far more still. Then drag the mass slider
to make the whole curve steeper: more mass lifts the energy at every speed.
When you brake, the road's friction has to remove all of the car's kinetic energy — turn
every joule of it into heat in the brakes and tyres. The distance that takes is set by how much
energy there is to get rid of, and that energy grows as v^2. So going
twice as fast means four times the energy to shed and roughly four times the
braking distance. It is why the gap between "30" and "70" in a road-safety leaflet looks so
shockingly large — and why a small extra push on the accelerator can turn a near-miss into a
serious crash. The same squared speed appears in aircraft (a jet needs a long runway because it
lands with huge kinetic energy) and in hydroelectric dams (fast-falling water carries far more
energy than slow water).