Potential Dividers
You have a 9\ \text{V} battery, but the little sensor you want to
drive needs exactly 5\ \text{V}. You have a
12\ \text{V} supply, but the microphone input expects a whisper of a
volt. How do you tap off a smaller, chosen slice of a voltage you already have — without
a fancy converter, using nothing but two resistors?
The answer is the potential divider: two (or more) resistors joined in
series across a supply. Because
they carry the same current, the supply voltage is shared out between them in proportion
to their resistances. Put a wire between the two resistors and you can pick off any
fraction of the supply you like — from nearly nothing up to nearly the whole thing. It is one of
the most useful little circuits in all of electronics: it sets reference voltages, it is the
volume knob on a stereo and the dimmer on a lamp, and — swap one resistor for a
thermistor or LDR — it is
the heart of every temperature and light sensor.
Where the equation comes from
Put two resistors R_1 and R_2 in series
across a supply V_\text{in}. The two
series rules do all the work.
First, the resistances add, so the current in the single loop is
I = \frac{V_\text{in}}{R_1 + R_2}.
That same current flows through both resistors. The potential difference
across each one is then just V = IR applied to that resistor:
V_1 = I R_1 = V_\text{in}\,\frac{R_1}{R_1 + R_2}, \qquad
V_2 = I R_2 = V_\text{in}\,\frac{R_2}{R_1 + R_2}.
If we take our output from across R_2 — a wire from
the point between the resistors, and a wire from the bottom of R_2 —
then V_\text{out} = V_2. Notice the two shares add straight back to the
whole supply, exactly as Rule 2 demands:
V_1 + V_2 = V_\text{in}. Nothing is lost; the supply is simply
divided.
Sharing in proportion
The whole idea lives in one clean formula: the fraction of the supply you tap off is the same as
the fraction of the total resistance sitting in your output resistor.
V_\text{out} = V_\text{in}\,\frac{R_2}{R_1 + R_2}
For two resistors R_1 and R_2 in series
across a supply V_\text{in}, carrying the same current:
-
The output taken across R_2 is
V_\text{out} = V_\text{in}\,\dfrac{R_2}{R_1 + R_2}.
-
The output taken across R_1 is
V_\text{out} = V_\text{in}\,\dfrac{R_1}{R_1 + R_2} — the
other resistor's share.
-
The two shares are in the ratio of the resistances:
\dfrac{V_1}{V_2} = \dfrac{R_1}{R_2}, and always add to the supply,
V_1 + V_2 = V_\text{in}.
Read it as a story. The bigger resistor grabs the bigger share
of the push, because the same current squeezing through a larger resistance drops a larger
voltage. Two useful limits check the formula at a glance: if
R_2 \gg R_1 the fraction approaches 1 and
V_\text{out} \to V_\text{in} (nearly all the supply lands on
R_2); if R_2 \ll R_1 the fraction approaches
0 and V_\text{out} \to 0. Everything in
between is a tunable slice of the supply.
Worked examples
Example 1 — read off an output. A 12\ \text{V} supply
sits across R_1 = 3\ \text{k}\Omega and
R_2 = 1\ \text{k}\Omega, and we tap the output across
R_2. Then
V_\text{out} = V_\text{in}\,\frac{R_2}{R_1 + R_2}
= 12 \times \frac{1}{3 + 1} = 12 \times \tfrac14 = 3\ \text{V}.
The units of resistance cancel in the ratio, so kΩ against kΩ is fine — you never have
to convert. The small resistor took the small share.
Example 2 — design for a target. We have a
9\ \text{V} supply and want
V_\text{out} = 5\ \text{V} across
R_2. Choosing R_2 = 10\ \text{k}\Omega, what
must R_1 be? Rearrange the divider equation for
R_1:
V_\text{out}(R_1 + R_2) = V_\text{in} R_2
\;\Rightarrow\; R_1 = R_2\left(\frac{V_\text{in}}{V_\text{out}} - 1\right)
= 10\left(\frac{9}{5} - 1\right) = 10 \times 0.8 = 8\ \text{k}\Omega.
Check: 9 \times \frac{10}{8 + 10} = 9 \times \frac{10}{18} = 5\ \text{V}.
Exactly the output we wanted. Designing a divider is nothing more than this rearrangement.
Example 3 — the ratio shortcut. Two resistors in series across
20\ \text{V} are in the ratio
R_1 : R_2 = 3 : 2. Without knowing the actual ohms, the voltage splits
in the same ratio, and the shares must total 20\ \text{V}:
V_1 = 20 \times \frac{3}{3 + 2} = 12\ \text{V}, \qquad
V_2 = 20 \times \frac{2}{3 + 2} = 8\ \text{V}.
Because only the ratio matters, 3\ \Omega and
2\ \Omega give the same split as
3\ \text{M}\Omega and 2\ \text{M}\Omega.
(Bigger resistors just draw a smaller current — handy when you want the divider to waste less
energy.)
Play with a divider
Here is the divider itself: the supply V_\text{in} across
R_1 (top) and R_2 (bottom) in series, with a
voltmeter reading the output V_\text{out} tapped across
R_2. Drag the sliders and watch the equation breathe:
- Raise R_2 and its share climbs — the output bar grows towards the
dashed full-supply mark.
- Raise R_1 instead and R_2's share
shrinks — the same current now drops more of its voltage up top.
- Set R_1 = R_2 and the supply splits exactly in half, whatever the
supply is.
The potentiometer: a divider you can turn
So far R_1 and R_2 have been two separate
resistors. But a potentiometer ("pot") is a single track of resistance with a
sliding contact — a wiper — that you turn or slide. The wiper splits the one
track into two parts: everything above it acts as R_1, everything below
as R_2. As you turn the knob, resistance moves smoothly from one side
to the other, so
V_\text{out} = V_\text{in}\,\frac{R_2}{R_1 + R_2}
sweeps continuously from 0 up to
V_\text{in} as you rotate from one end to the other. That is a
variable potential divider — an output you dial in by hand. Every volume knob, every
light dimmer, every old-style joystick and every sliding fader on a mixing desk is exactly this: a
potentiometer picking off an adjustable fraction of a fixed supply, which the rest of the circuit
then reads.
Sensor dividers: light and heat that switch things on
The real magic happens when you replace one of the resistors with a
thermistor or LDR — a
resistor whose value changes with its surroundings. Now the split shifts on its own as
the world changes, turning "it got hot" or "it went dark" into a moving output voltage that a
switching circuit can act on.
-
A temperature alarm. Put a thermistor as R_1 and a
fixed resistor as R_2. As it gets hot the thermistor's resistance
falls, so it keeps a smaller share and more of the supply appears
across the fixed resistor — V_\text{out} rises. Wire
the output to a switch and it trips when the temperature crosses a set point.
-
A dusk-sensing light. Put an LDR as R_2 and take the
output across it. As night falls the LDR's resistance rises, so it grabs a
bigger share and V_\text{out} climbs. When
it passes the switching level the lamp comes on — then reverses at dawn.
The direction of the switching is entirely in your hands: which component you make the
output resistor decides whether "hotter", "colder", "brighter" or "darker" is the event
that raises the output. Same equation, four different alarms — just swap what you tap across.
Worked example — a thermistor divider. A 6\ \text{V}
supply feeds a thermistor in series with a fixed
2\ \text{k}\Omega resistor, output taken across the fixed resistor. On
a cold morning the thermistor reads 10\ \text{k}\Omega; warmed by a
fire it drops to 1\ \text{k}\Omega. The output goes from
V_\text{out}^\text{cold} = 6 \times \frac{2}{10 + 2} = 1\ \text{V}
\qquad\longrightarrow\qquad
V_\text{out}^\text{hot} = 6 \times \frac{2}{1 + 2} = 4\ \text{V}.
A single degree of heating has swung the output from 1\ \text{V} to
4\ \text{V} — a big, clean signal for a switch to latch onto. That
swing, from a two-resistor circuit, is why potential dividers are everywhere.
Three traps snare almost everyone with dividers:
-
Tap the right resistor. V_\text{out} is the share
across the resistor you take the output from. Output across
R_2 is V_\text{in}\dfrac{R_2}{R_1 + R_2};
output across R_1 is
V_\text{in}\dfrac{R_1}{R_1 + R_2}. Putting the wrong
resistance on top of the fraction is the single most common slip — always ask "across which one
am I measuring?" and put that resistance in the numerator.
-
Proportion, not equal shares. The supply is not split evenly unless
the resistors are equal. The bigger resistor takes the bigger
share of the voltage — a 9\ \Omega and a
1\ \Omega resistor across 10\ \text{V}
split it 9\ \text{V} and 1\ \text{V}, not
5 and 5.
-
Loading changes the output. The formula assumes no current is drawn from
the output. Connect a real load (say a component of resistance
R_L) across R_2 and it sits in
parallel with
R_2, lowering that combined resistance — so the true output
drops below the ideal value. This is the loading effect. To
keep it small, make the load's resistance much larger than R_2 (or
use a buffer). It is why a voltmeter needs a huge resistance: so it reads the divider without
disturbing it.
Wiggle an old analogue joystick or a game-controller thumbstick and, underneath, you are turning
two potentiometers — one for left–right, one for up–down. Each is a potential
divider: a fixed supply across a resistive track, with a wiper the stick nudges along it. Push the
stick east and the wiper slides one way, changing R_1 and
R_2 so V_\text{out} rises; pull it west and
the output falls. The console simply measures those two output voltages many times a second and
reads your hand's position straight off them.
The same trick runs the volume of your music (a pot picking off a bigger or smaller slice of the
audio signal), the dimmer on a dining-room light, and the throttle on an electric scooter. A
strip of resistance and a sliding contact — the humble divider — quietly turns the twist of your
wrist into a number a circuit can obey.