Electric Fields
You already know from
static electricity that
charged objects push and pull on one another without touching — a comb lifts scraps of
paper, like charges shove apart, unlike charges snap together. But how strong is that
force, exactly? How does it fade as the charges move apart? And what invisible thing reaches across
the empty gap to carry the push?
At A-level we answer all three the same way Newton answered them for gravity. Charge, like mass,
fills the space around it with a field — a region where any other charge feels a
force — and that field weakens with distance in exactly the same
inverse-square way.
The parallel is so close that once you have the gravity picture in your bones, electric fields fall
almost straight out of it — with one dramatic new twist: charges come in two signs,
so electric forces can repel as well as attract.
Coulomb's law: the force between two charges
In the 1780s Charles-Augustin de Coulomb measured the force between two small charged spheres with a
delicate torsion balance and found a law that looks uncannily like Newton's law of gravitation. The
force grows with each charge and shrinks with the square of their separation.
The electrostatic force between two point charges Q_1 and
Q_2 a distance r apart is
F = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q_1 Q_2}{r^2},
- it acts along the straight line joining the charges, and is repulsive for like
charges (both signs the same) and attractive for unlike charges;
- it is an inverse-square law: double r and the force
drops to a \tfrac14, treble it and it drops to a
\tfrac19;
- the constant is
\dfrac{1}{4\pi\varepsilon_0} \approx 8.99\times10^{9}\ \text{N}\,\text{m}^2\,\text{C}^{-2},
where \varepsilon_0 = 8.85\times10^{-12}\ \text{F}\,\text{m}^{-1} is the
permittivity of free space;
- the electric field strength is the force per unit positive charge,
E = \dfrac{F}{Q}, \qquad E_{\text{radial}} = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q}{r^2},
measured in N/C (equivalently V/m), and between parallel
plates the field is uniform, E = \dfrac{V}{d}.
Unlike G, the electric constant is enormous — about
8.99\times10^{9} versus gravity's
6.67\times10^{-11}. That is why the electric force between two protons is
some 10^{36} times stronger than their gravitational pull, and why it is
electricity, not gravity, that holds atoms and molecules — and you — together.
Worked example — the force between two charges
Two small spheres carry Q_1 = +3\ \mu\text{C} and
Q_2 = +2\ \mu\text{C}, held
r = 0.50\ \text{m} apart. Find the force between them.
Step 1 — write Coulomb's law.
F = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q_1 Q_2}{r^2}.
Step 2 — substitute (charges in coulombs: 3\ \mu\text{C} = 3\times10^{-6}\ \text{C}).
F = (8.99\times10^{9})\dfrac{(3\times10^{-6})(2\times10^{-6})}{(0.50)^2}.
Step 3 — evaluate. The top is
(8.99\times10^{9})(6\times10^{-12}) = 5.39\times10^{-2}, and the bottom is
0.25, so
F \approx 0.22\ \text{N}.
Both charges are positive — like — so this force is repulsive: it pushes the
two spheres apart. Had one charge been negative, the same size of force would pull them
together. Gravity never gets that choice: mass only ever attracts.
The electric field of a point charge
Rather than recompute the force for every different test charge, we describe the space itself
once. The electric field strength E at a point is the force
a unit positive charge would feel there — a property of the location, set by the
source charge, not by whatever we drop into it:
E = \dfrac{F}{Q} \quad\Longrightarrow\quad F = EQ.
For a single point (or spherical) charge Q, putting Coulomb's law over one
coulomb of test charge gives the radial field
E = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q}{r^2},
which — just like gravity's g = GM/r^2 — is a vector that
obeys the inverse-square law and depends only on the source charge and the distance from it. Its
direction is where the sign steps in: because E is the
force on a positive charge, the field points away from a positive source (a
positive test charge is repelled outward) and towards a negative source (a positive
test charge is pulled inward).
Worked example — field near a point charge
A point charge Q = +5\ \mu\text{C} sits in a vacuum. Find the field strength
a distance r = 0.10\ \text{m} away.
E = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q}{r^2} = (8.99\times10^{9})\dfrac{5\times10^{-6}}{(0.10)^2} \approx 4.5\times10^{6}\ \text{N/C}.
The field points radially outward (the source is positive). Drop a charge
q = -2\ \text{nC} at that spot and it feels a force
F = Eq = (4.5\times10^{6})(2\times10^{-9}) \approx 9.0\times10^{-3}\ \text{N},
directed towards the source because the test charge is negative.
Field lines: picturing the field
We draw a field as a set of field lines — arrows showing the direction a positive
test charge would be pushed. For a point charge the lines are radial: straight
spokes running out of a positive charge and into a negative one. Where the lines
crowd together the field is strong; where they spread apart it is weak — which is exactly why the
field is fiercest close in and fades with distance. Flip the sign below and watch every arrow reverse.
Two rules never break: field lines start on positive charge and end on negative charge
(or run off to infinity), and they never cross — if they did, the field would point
two ways at once at the crossing point, which is nonsense.
See the inverse-square fall
The curve below is E = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q}{r^2} for a
+1\ \text{nC} charge (so \tfrac{1}{4\pi\varepsilon_0}Q \approx 9
and E \approx 9/r^2\ \text{N/C}). Drag the slider outward and watch how
fast the field collapses: it is already quartered by r = 2\ \text{m}
and down to a ninth by r = 3\ \text{m}. That steep, never-quite-zero shape is
the fingerprint of every inverse-square law — gravity and electricity share it exactly.
The uniform field between parallel plates
Bring two flat metal plates close together and connect them to a supply, so one is at a higher
potential than the other. Between them the field is completely different from the radial spray of a
point charge: the field lines are straight, parallel and evenly spaced, all running
from the positive plate to the negative one. Evenly spaced lines mean a uniform field
— the same strength everywhere in the gap — given by the beautifully simple
E = \dfrac{V}{d},
where V is the potential difference between the plates and
d their separation. This is where the alternative unit V/m
for field strength comes from. Slide the voltage and separation below and watch the field readout
respond.
Worked example — deflecting a charge
Two plates d = 0.05\ \text{m} apart have a potential difference of
V = 200\ \text{V}. Find the field, and the force on an electron
(q = 1.6\times10^{-19}\ \text{C}) passing between them.
E = \dfrac{V}{d} = \dfrac{200}{0.05} = 4000\ \text{N/C}.
F = Eq = (4000)(1.6\times10^{-19}) = 6.4\times10^{-16}\ \text{N}.
Tiny — but an electron is so light that this steady sideways push flings it into a smooth parabolic
curve, exactly like a ball thrown in gravity's uniform field near the ground. That is the trick behind
the old cathode-ray tube and the ink-jet printer.
The gravity–electricity analogy
Line the two field laws up side by side and the resemblance is almost complete. Learn one column and
you very nearly get the other for free — the algebra is identical; only the source quantity,
the constants, and (crucially) the possibility of repulsion change.
| Idea | Gravitational field | Electric field |
| Source of the field | mass m | charge Q |
| Force law |
F = \dfrac{G m_1 m_2}{r^2} |
F = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q_1 Q_2}{r^2} |
| Constant |
G = 6.67\times10^{-11} |
\dfrac{1}{4\pi\varepsilon_0} = 8.99\times10^{9} |
| Field strength (definition) |
g = \dfrac{F}{m} |
E = \dfrac{F}{Q} |
| Radial field |
g = \dfrac{GM}{r^2} |
E = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q}{r^2} |
| Units | N/kg | N/C (= V/m) |
| Force can be… |
only attractive |
attractive OR repulsive |
The single deep difference sits in the last row. Mass comes in only one flavour, so gravity always
pulls inward. Charge comes in two, so an electric field can drive a charge either way — and that is the
whole reason electricity can do such intricate work that gravity never could.
These are the classic A-level traps — check yourself against all four:
-
Electric fields can repel. Coulomb's law and Newton's gravitation look
identical, but gravity only ever attracts, whereas two like charges push apart. Always
check the signs: like → repel, unlike → attract.
-
Field strength is force per unit positive charge. That is why
E points the way a positive charge would move — out of a
positive source, into a negative one. A negative test charge feels a force in the
opposite direction to the field.
-
E = V/d is only for the uniform field between parallel
plates. It does not give the field of a point charge — for that you must use the
inverse-square E = \tfrac{1}{4\pi\varepsilon_0}Q/r^2. Match the equation to
the geometry.
-
It is inverse-square, not inverse. Doubling the distance from a point
charge quarters the field, not halves it. Square the distance ratio every time.
Both are uniform electric fields at work. In a continuous ink-jet printer, a nozzle
breaks the ink into a stream of tiny droplets and gives each one a controlled charge. The stream then
flies between two charged deflector plates — a uniform field E = V/d — and
the field pushes each droplet sideways by an amount that depends on its charge, steering it to the
right spot on the page (or letting uncharged drops fly straight into a gutter to be recycled). Whole
characters are painted this way, thousands of droplets a second.
The old cathode-ray tube television did the same to a beam of electrons. An electron
gun fired a beam down the tube; deflector plates (or coils) swept it left–right and up–down across the
phosphor screen, lighting a glowing dot that raced back and forth fast enough to paint an entire moving
picture. Every chunky old TV and computer monitor was, at heart, a charged particle being flung around
by F = Eq in a field you can now calculate.