Capacitance
Press the shutter on a camera in a dark room and, a heartbeat later, the flash fires — a dazzling
burst far brighter than the little battery inside could ever manage on its own. Listen closely
beforehand and you may even hear a rising whine as the camera gets ready. What is happening is that
a single component spends a second or two quietly hoarding electric charge, then
dumps the whole lot in one blinding instant. That component is a capacitor.
A capacitor is beautifully simple: two conducting plates held close together but
separated by an insulator (called the dielectric) so that no charge can
cross the gap. Connect it to a battery and electrons are pulled off one plate and piled onto the
other: one plate ends up positive, the other equally negative.
Charge Q builds on the plates, and a potential difference
V grows across them, until that voltage matches the supply and the flow
stops. The capacitor is now charged — it holds a store of charge, and with it a
store of energy, ready to be released the moment you give it a path.
This page asks the two questions that make capacitors useful: how much charge does a given
capacitor hold at a given voltage, and how much energy is packed into it — and then, how
that store leaks away when you finally let it flow.
Capacitance: charge stored per volt
Push a capacitor to a higher voltage and it grabs proportionally more charge — double the voltage,
double the charge on the plates. The constant of proportionality, the charge held for each volt
across the plates, is the capacitor's capacitance, written
C:
C = \dfrac{Q}{V}.
Here Q is the charge in coulombs
(\text{C}), V the potential difference in
volts (\text{V}), and C the
capacitance in farads (\text{F}). Read the meaning
straight off the units:
1\ \text{F} = 1\ \dfrac{\text{C}}{\text{V}} = \text{one coulomb of charge stored for every volt across the plates.}
Capacitance is a property of the capacitor itself — its plate area, their spacing, and the
dielectric between them — not of how much you happen to have charged it. A bigger
C stores more charge at the same voltage: a roomier
bucket for charge.
Worked example 1 — finding the capacitance. A capacitor holds
60\ \mu\text{C} of charge when there is
12\ \text{V} across it. What is its capacitance?
C = \dfrac{Q}{V} = \dfrac{60\times10^{-6}\ \text{C}}{12\ \text{V}} = 5\times10^{-6}\ \text{F} = 5\ \mu\text{F}.
Worked example 2 — finding the charge. That same
5\ \mu\text{F} capacitor is now charged to
20\ \text{V}. Rearranging C = Q/V gives
Q = CV:
Q = CV = 5\times10^{-6}\ \text{F} \times 20\ \text{V} = 100\times10^{-6}\ \text{C} = 100\ \mu\text{C}.
Look at a real capacitor and it is stamped with something like
100\ \mu\text{F}, 10\ \text{nF} or
22\ \text{pF} — never a plain "2 F". That is because the farad is
a colossal unit. A one-farad capacitor would hold a whole coulomb of charge at just one
volt, and a coulomb is an enormous pile of electrons; to build one out of flat plates you would
need a sheet the size of a sports field. So everyday capacitors are measured in
microfarads (1\ \mu\text{F} = 10^{-6}\ \text{F}),
nanofarads (10^{-9}) and
picofarads (10^{-12}). The chunky "supercapacitors"
now used to back up memory chips and smooth electric-car power really do reach several farads —
and they are marvels of packed-up surface area to manage it.
The energy stored: a triangle under the Q–V graph
Charging a capacitor takes work: you are forcing more and more charge onto a plate that is
already charged up and pushing back. Crucially, the voltage does not stay put while you do it — it
rises from zero as the charge builds, because V = Q/C.
Plot charge Q against voltage V and you get a
straight line through the origin (its gradient is the capacitance
C). The energy stored is the area underneath that line —
and the area of a triangle is \tfrac12 \times \text{base} \times \text{height}:
E = \tfrac12 QV.
Because Q = CV, the very same energy can be written three equivalent ways
— reach for whichever pair of quantities you happen to know:
E = \tfrac12 QV = \tfrac12 CV^2 = \dfrac{Q^2}{2C}.
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Capacitance is the charge stored per unit voltage across the plates:
C = \dfrac{Q}{V}, measured in farads, where
1\ \text{F} = 1\ \text{C/V}. This rearranges to
Q = CV.
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The energy stored is the triangular area under the Q–V
graph, so it carries a factor of one half:
E = \tfrac12 QV = \tfrac12 CV^2 = \dfrac{Q^2}{2C}.
Worked example 3 — the energy stored. The
5\ \mu\text{F} capacitor from before is charged to
20\ \text{V}. How much energy does it hold?
E = \tfrac12 CV^2 = \tfrac12 \times 5\times10^{-6}\ \text{F} \times (20\ \text{V})^2 = 1\times10^{-3}\ \text{J} = 1\ \text{mJ}.
Check it against the other formula — with Q = 100\ \mu\text{C},
E = \tfrac12 QV = \tfrac12 \times 100\times10^{-6} \times 20 = 1\ \text{mJ}.
The two forms agree, as they must.
Drag the sliders below to build a capacitor's charge up to a chosen voltage. The straight line is
Q = CV; the shaded triangle under it is the energy
\tfrac12 QV you are storing. Notice that pushing to a higher voltage
grows the triangle in two directions at once — taller and wider — which is why the
energy climbs with V^2, not just with V.
Discharging: an exponential fall, and the time constant
Now give the charged capacitor somewhere to go. Connect it across a resistor
R and it drives a current that carries its charge away. But here is the
twist: as charge leaks off, the voltage drops, so the current it can drive drops too — which means
the charge leaks away more slowly. A quantity whose rate of change is proportional to how
much is left always falls in the same shape: an exponential decay.
Q = Q_0\,e^{-t/RC}.
The voltage and current fall in exactly the same way — V = V_0\,e^{-t/RC}
and I = I_0\,e^{-t/RC} — because each is just a fixed multiple of the
charge. The rate of the fall is set entirely by the combination
RC, and this combination is so important it gets its own name and symbol,
the time constant \tau (Greek "tau"):
\tau = RC.
Put t = \tau into the formula and the exponent becomes
-1, so Q = Q_0\,e^{-1} \approx 0.37\,Q_0. The
time constant is the time for the charge (or voltage, or current) to fall to
1/e \approx 37\% of its starting value. A bigger
R or C makes \tau
bigger, so the capacitor charges and discharges more slowly. After about
5\tau the charge has dropped below 1\% — the
capacitor is, for all practical purposes, fully discharged.
Worked example 4 — the time constant. A
470\ \mu\text{F} capacitor discharges through a
10\ \text{k}\Omega resistor. Its time constant is
\tau = RC = 10\,000\ \Omega \times 470\times10^{-6}\ \text{F} = 4.7\ \text{s}.
Worked example 5 — charge left after a time. A capacitor is charged to
Q_0 = 100\ \mu\text{C} and discharges with time constant
\tau. How much charge remains after two time constants,
t = 2\tau?
Q = Q_0\,e^{-t/RC} = 100\ \mu\text{C} \times e^{-2} = 100 \times 0.135 = 13.5\ \mu\text{C}.
After one \tau it was 37\ \mu\text{C}; after
two, 13.5\ \mu\text{C}; after five, well under one microcoulomb. Each
time constant knocks the charge down by the same factor, never by the same amount — that is
the signature of exponential decay.
The curve below is a live discharge, Q = Q_0\,e^{-t/RC}. Turn the
resistance and capacitance sliders and watch the whole decay stretch or squeeze: the marked point
is one time constant \tau = RC, where the charge has fallen to the
37\% line, and the far marker shows where — after about
5\tau — the capacitor is essentially empty.
What capacitors are for
This little charge-and-release trick turns out to be everywhere:
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Smoothing power supplies. The mains delivers a lumpy, pulsing voltage after it
is rectified. A big capacitor across the output charges up on each pulse and discharges through
the gaps, filling in the dips so your laptop sees a nice steady voltage.
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Camera flashes and defibrillators. A capacitor charges slowly from a modest
battery, then dumps its stored energy in a single high-power burst — a flash of light, or a
life-saving jolt — that the battery alone could never deliver.
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Timing circuits. Because \tau = RC is a known, chosen
delay, an RC pair sets the tempo of blinking lights, windscreen-wiper
intervals and simple clocks.
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Backup memory. A charged capacitor can keep a chip's settings or a clock ticking
for minutes or hours after the power is pulled, while you swap the batteries.
That rising whine before a camera flash is the sound of a small circuit frantically pumping the
battery's 1.5\ \text{V} up to a few hundred volts to charge the flash
capacitor; when it is full, the whine peaks and the flash is armed. Fire it, and the capacitor
empties through the flash tube in a few thousandths of a second — a tiny stored energy delivered
at huge power, which is what makes the light so bright.
The flip side is a genuine hazard. A capacitor does not forget its charge when you switch the
power off — with nothing to discharge through, it can sit fully charged for a very long time.
The large capacitors inside an old television or a microwave oven can hold a dangerous,
even lethal, charge for minutes to hours after the plug is pulled. That is exactly why
engineers deliberately short the plates out with a resistor before poking
around inside — the capacitor is patiently waiting, and it does not care that the set is
unplugged.
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The energy is \tfrac12 QV, not QV.
The one-half is not optional and it is not a units fudge. As the capacitor charges, the voltage
climbs from zero, so on average each scrap of charge is pushed through only half the
final voltage. Geometrically, the energy is the triangle under the
Q–V graph, not the full rectangle. (Moving
charge across a fixed pd — a battery — is E = QV with no half; a
capacitor is different precisely because its voltage builds up.)
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Bigger R or C means
slower, not faster. Since \tau = RC, increasing
either lengthens the time constant, so the capacitor takes longer to charge or
discharge. It is tempting to think "bigger resistor = quicker" — the opposite is true.
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A capacitor is not discharged the instant you disconnect it. The decay is
exponential: it approaches zero but reaches it only in the limit. In practice you must wait
about 5\tau (or short it out) before treating it as safe and empty —
never assume "power off" means "capacitor empty".