z-Scores
Is a height of 190\,\text{cm} "tall"? Is a test score of
85 "good"? You genuinely cannot say — not from the number alone.
190\,\text{cm} is towering in a room of jockeys and unremarkable in a
line-up of basketball centres; 85 is brilliant if the class average was
60 and mediocre if it was 90. To judge a value
you need to know two things about the crowd it came from: where the middle is, and
how spread out the crowd is.
The z-score bottles exactly that judgement into a single number. It measures a value
in units of
standard deviations
from the mean:
z = \frac{x - \mu}{\sigma}.
It answers one universal question: how many standard deviations is
x away from the mean? Whatever the value measured —
centimetres, marks, seconds, dollars — the z-score comes out as a pure "how unusual is this" number
that any two situations can be compared on.
Reading the sign
- z > 0 — the value is above the mean.
- z < 0 — the value is below the mean.
- z = 0 — the value is the mean exactly.
So z = -2 means "two standard deviations below the mean", and
z = 1.5 means "one and a half standard deviations above it". The size
of |z| tells you how unusual the value is — by the empirical rule, a
z beyond \pm 2 is already quite rare, and one
beyond \pm 3 is a genuine outlier.
Worked example 1 — compute and interpret
A cohort's exam scores are normal with mean \mu = 72 and standard
deviation \sigma = 8. Priya scored 88. What is
her z-score, and what does it mean?
Plug straight into the formula:
z = \frac{x - \mu}{\sigma} = \frac{88 - 72}{8} = \frac{16}{8} = 2.
Her z = +2: she is two standard deviations above average.
That is a strong result — by the empirical rule only about 2.5\% of the
cohort sits above z = 2, so she is roughly in the top
1 in 40. Notice the units cancelled: the
16 marks in the numerator and the 8 marks in
the denominator leave a bare 2.
Worked example 2 — compare across different tests
Here is where z-scores earn their keep. Sam scores 90 on a
hard test (mean 70, SD 10). Lee scores
95 on an easy test (mean 90, SD
2). Lee's raw mark is higher — but who actually did better relative to
their test?
Standardise both:
z_{\text{Sam}} = \frac{90 - 70}{10} = 2.0, \qquad z_{\text{Lee}} = \frac{95 - 90}{2} = 2.5.
Lee's z = 2.5 beats Sam's z = 2.0, so
Lee's result is the more exceptional — even though on the hard test
90 "feels" more impressive. The raw numbers are not comparable; the
z-scores are. Whenever a spread differs, only 2 points above a
tight mean (\sigma = 2) can outrank 20 points
above a loose one (\sigma = 10).
Worked example 3 — turn a z-score into a percentile
Because the empirical rule tells you the area under a bell curve, a z-score can be read as a rough
percentile — what fraction of the crowd you are above. Take Priya's
z = +2 from example 1.
The rule says 95\% lies within 2\sigma, so
5\% lies outside, split as 2.5\% in each tail.
The fraction below z = 2 is therefore everything except the upper
tail:
100\% - 2.5\% = 97.5\%.
Priya is at about the 97.5th percentile — higher than roughly
97.5\% of the cohort. The same reasoning gives quick percentiles at the
landmark z-scores: z = 0 \to 50\text{th},
z = 1 \to 84\text{th} (since 100\% - 16\% = 84\%),
z = -1 \to 16\text{th}.
Slide the z-marker
Drag the slider to move the marker to x = z on the standard normal
curve. Read off where it lands: near the centre for small |z|, far out
in a thin tail as |z| grows toward 3.
- z = \dfrac{x - \mu}{\sigma} counts how many standard deviations x sits from the mean.
- z > 0 is above the mean, z < 0 below, z = 0 at the mean.
- z-scores remove the units, so values from different distributions become directly comparable — the higher z is more exceptional.
A tempting mistake: "I computed z-scores, so now my data is normal and I can use the
68–95–99.7 rule."
Not so. Subtracting the mean and dividing by \sigma only shifts
and rescales the values so they have mean 0 and SD
1. It slides and stretches the picture — it does not change its
shape.
If the original data was skewed, the z-scores are exactly as skewed. The arithmetic is perfectly
valid — every value still has a well-defined z — but you may not then claim
"95\% lie within z = \pm 2", because that
percentage is a property of the bell shape, which the raw data never had. z-scores
standardise position, never shape. Turning a value into a percentile via the
empirical rule only works when the distribution was already (approximately) normal to begin with.
z-scores are the machinery behind the scoreboards you already know. Standardised tests like the
SAT and IQ scales don't report raw marks at all — they convert
each person's raw score to a z-score, then map that onto a fixed, friendly scale. IQ, for instance,
is built to have mean 100 and SD 15, so an IQ
of 130 is simply z = +2 dressed up in nicer
numbers. "Grading on a curve" is the same trick: a teacher standardises the class's raw marks and
assigns letter grades by z-score bands, so the shape of the class decides the grades, not a
fixed pass mark.
Sports analysts lean on it hardest of all. How do you compare a hitter from the
1920s with one from today, when the whole league's averages have drifted?
You standardise each player against their own era's mean and spread. A "+3
z-score season" is dominant whether it happened in 1927 or
2024 — the z-score quietly cancels the era, the league, and the units, and
leaves only "how far above everyone else they stood".
See it explained