The Divisor Functions

The most natural questions to ask about a number's divisors: how many are there, and what do they add up to? Both answers are multiplicative functions, so both fall straight out of the prime factorisation.

Counting divisors: \tau(n)

Write \tau(n) (also d(n)) for the number of positive divisors. A divisor of n = p_1^{a_1}\cdots p_k^{a_k} is built by choosing each prime's exponent independently, from 0 up to a_i β€” that's a_i + 1 choices each:

\tau(n) = (a_1 + 1)(a_2 + 1)\cdots(a_k + 1).

So \tau(12) = \tau(2^2\cdot 3) = (2+1)(1+1) = 6 β€” and indeed 12 has divisors 1,2,3,4,6,12.

Summing divisors: \sigma(n)

Write \sigma(n) for the sum of the divisors. On a single prime power the divisors form a geometric series, giving a tidy closed form:

\sigma(p^{a}) = 1 + p + p^2 + \cdots + p^{a} = \frac{p^{a+1} - 1}{p - 1},

and multiplicativity stitches the prime powers together:

\sigma(12) = \sigma(2^2)\,\sigma(3) = (1+2+4)(1+3) = 7 \cdot 4 = 28.

Reading a number's character

These functions reveal a number's "shape". A prime has \tau(p) = 2 (only 1 and itself); a perfect square has an odd \tau (its square root is unpaired). And comparing \sigma(n) against n sorts numbers into deficient, abundant, and the rare perfect β€” the subject of the next page.