Cauchy's Integral Theorem

On the previous page we saw that contour integrals of powers around the unit circle almost always vanished — only 1/z, which is not holomorphic at the origin, survived. That was a hint of a sweeping law. Cauchy's integral theorem says the vanishing was no coincidence:

No singularity inside the loop means no net contribution. Let us prove it by turning the complex integral into two real ones and unleashing Green's theorem.

Deriving it from Green's theorem

Write f = u + iv and dz = dx + i\,dy. We expand the product and collect real and imaginary line integrals, then convert each with Green's theorem.

Step 1 — expand the integrand. Multiply (u + iv)(dx + i\,dy):

(u + iv)(dx + i\,dy) = (u\,dx - v\,dy) + i\,(v\,dx + u\,dy).

Step 2 — split into two real circulations. So the contour integral is a real line integral plus i times another:

\oint_\gamma f\,dz = \oint_\gamma (u\,dx - v\,dy) + i\oint_\gamma (v\,dx + u\,dy).

Step 3 — apply Green's theorem to each. Green's theorem turns a circulation \oint (P\,dx + Q\,dy) into the double integral \iint_D (Q_x - P_y)\,dA over the enclosed region D. For the first integral P = u,\ Q = -v; for the second P = v,\ Q = u:

\oint_\gamma f\,dz = \iint_D (-v_x - u_y)\,dA + i\iint_D (u_x - v_y)\,dA.

Step 4 — invoke Cauchy–Riemann. Because f is holomorphic, the Cauchy–Riemann equations u_x = v_y and u_y = -v_x hold throughout D. Read off each integrand:

-v_x - u_y = -v_x - (-v_x) = 0, \qquad u_x - v_y = u_x - u_x = 0.

Step 5 — conclude. Both double integrals are integrals of zero, so

\oint_\gamma f(z)\,dz = 0.

The Cauchy–Riemann equations are precisely the conditions that make both Green's-theorem integrands vanish. Holomorphy and a vanishing loop integral are two faces of the same fact.

Path-independence

A vanishing loop integral has an immediate, powerful consequence. Take two points z_0 and z_1 and two paths \gamma_1, \gamma_2 from one to the other. Traverse \gamma_1 forwards and \gamma_2 backwards: together they form a closed loop, so by Cauchy's theorem the total is zero. Reversing a path negates its integral, hence

\int_{\gamma_1} f\,dz - \int_{\gamma_2} f\,dz = 0 \quad\Longrightarrow\quad \int_{\gamma_1} f\,dz = \int_{\gamma_2} f\,dz.

For a holomorphic f, the value of \int f\,dz between two points does not depend on which route you take — only on where you start and where you end. This is exactly the behaviour of a gradient field in real vector calculus, and it lets us define an antiderivative F with F' = f and write \int_{z_0}^{z_1} f\,dz = F(z_1) - F(z_0), a complex fundamental theorem of calculus. The freedom to deform a contour without changing its integral is the engine behind Cauchy's integral formula and the whole residue calculus to come.

Bend the path, keep the answer

The two coloured curves both run from z_0 to z_1. Bend the upper path with the bow slider: provided f is holomorphic in the region they enclose, both give the same integral, and the closed loop formed by going out along one and back along the other integrates to zero — Cauchy's theorem in a picture.