The eigenvalue problem at its heart
Separation turns the spatial part into a boundary-value problem for X:
X'' = -\lambda X, \qquad X(0) = X(L) = 0.
This is an eigenvalue problem — the continuous cousin of
eigenvectors and eigenvalues.
Only special values \lambda_n = (n\pi/L)^2 admit a nonzero solution
satisfying the boundary conditions, and the solutions are the eigenfunctions
X_n(x) = \sin\frac{n\pi x}{L}, \qquad n = 1, 2, 3, \dots
The boundary conditions act as a sieve, selecting a discrete spectrum of allowed modes — exactly
the sines that Fourier series
are built from. That is no coincidence: it is why Fourier series are the natural language
for these problems.
- Seek u = X(x)T(t); substitute to get \frac{X''}{X} = \frac{1}{\alpha}\frac{T'}{T} = -\lambda (heat) or similar.
- The homogeneous boundary conditions make X'' = -\lambda X an eigenvalue problem with eigenvalues \lambda_n = (n\pi/L)^2 and eigenfunctions \sin(n\pi x/L).
- Superpose the product solutions and use the initial data to fix the coefficients (a Fourier series).