Sigma Notation

Every time a spreadsheet totals a column, a shop tallies a month of takings, or a scientist averages a thousand readings, the same thing is happening underneath: a long list of numbers is being added up. Mathematics needed a compact way to say "add all of these," and that is what sigma notation gives you.

Add up every whole number from 1 to 100. Written out in full, 1 + 2 + 3 + \dots + 98 + 99 + 100 is a mouthful — and that is a short sum. Real mathematics is full of sums with hundreds of terms, or a number of terms that depends on some n you haven't chosen yet. Writing them all out is hopeless.

So mathematicians invented a single symbol that means "add all of these up": the Greek capital sigma, \sum. Give it a formula, a start value, and an end value, and it packs an entire sum into one tidy instruction:

\sum_{k=1}^{100} k \;=\; 1 + 2 + 3 + \dots + 100.

That compact bundle on the left says exactly the same thing as the long trail on the right — it is just a far better way to write it, and to reason about it.

Reading the recipe

Sigma notation is a recipe with four parts. Take a small example:

\sum_{k=1}^{5} k \;=\; 1 + 2 + 3 + 4 + 5 \;=\; 15.

The letter k is the index (a counter). It starts at the number below the sigma — the lower limit — climbs by one each time, and stops at the number on top — the upper limit. The expression after the sigma is the general term (or summand): substitute each value of k into it and add all the results.

The general term can be any rule at all. Whatever it is, you substitute k = 1, 2, 3, \dots up to the top, then total the terms:

\sum_{k=1}^{4} 2k \;=\; 2 + 4 + 6 + 8 \;=\; 20, \sum_{k=1}^{3} k^2 \;=\; 1 + 4 + 9 \;=\; 14.

The lower limit need not be 1. In \sum_{k=2}^{4} k^2 = 4 + 9 + 16 = 29 the counter runs from 2 to 4, so there are three terms. This is exactly how an arithmetic or geometric series is written compactly — the general term is just the sequence's nth-term rule.

In \displaystyle\sum_{k=1}^{n} a_k:

Watch a sigma unpack

Step through \displaystyle\sum_{k=1}^{4} k^2: substitute each index value, square it, and total. Notice the answer collapses to a single number.

Worked example — sum of a linear rule

Evaluate \displaystyle\sum_{r=1}^{4} (3r - 1). (The index is called r here — the letter doesn't matter.) Substitute r = 1, 2, 3, 4 into 3r - 1:

(3\cdot 1 - 1) + (3\cdot 2 - 1) + (3\cdot 3 - 1) + (3\cdot 4 - 1) = 2 + 5 + 8 + 11 = 26.

Four terms (from 4 - 1 + 1 = 4), each worked out and added. The result is just the number 26 — no r left in sight.

Two results worth memorising

Some sums come up so often they have closed formulas — no need to add term by term. The simplest is a sum of a constant. If every one of n terms equals 1, the total is just n:

\sum_{k=1}^{n} 1 = n.

The other is the sum of the first n counting numbers, the very 1 + 2 + \dots + n we opened with. A schoolboy Gauss famously spotted its formula in seconds:

\sum_{k=1}^{n} k = \frac{n(n+1)}{2}.

Try it on our opening challenge: \sum_{k=1}^{100} k = \frac{100\cdot 101}{2} = 5050 — all one hundred numbers added, with no adding at all.

Splitting and scaling a sum

Because a sigma is just an addition in disguise, it obeys the ordinary rules of adding. Two shortcuts make sums much easier to handle. First, a constant multiplier can be pulled out to the front — since it multiplies every single term:

\sum_{k=1}^{n} c\,a_k \;=\; c \sum_{k=1}^{n} a_k.

Second, a sum of two rules splits into two separate sums (you can add the terms in any order you like):

\sum_{k=1}^{n} (a_k + b_k) \;=\; \sum_{k=1}^{n} a_k \;+\; \sum_{k=1}^{n} b_k.

Together these turn a scary-looking sum into pieces you already know. For instance, using the two results above,

\sum_{k=1}^{n} (2k + 3) \;=\; 2\sum_{k=1}^{n} k \;+\; \sum_{k=1}^{n} 3 \;=\; 2\cdot\frac{n(n+1)}{2} + 3n \;=\; n(n+1) + 3n \;=\; n^2 + 4n.

No term-by-term slog — just split, scale, and slot in the standard formulas.

The letter under the sigma (the index, usually i, r, or k) is a dummy variable. It is not an unknown you solve for — it is just a counter that ticks through the terms and then vanishes. So \sum_{k=1}^{3} k^2 and \sum_{i=1}^{3} i^2 are the same sum; renaming the counter changes nothing. And the finished value is a single number (or a formula in n) — never an expression that still contains k. If a k survives in your answer, you forgot to substitute.

The other classic slip is an off-by-one in the limits. Always count the terms with (\text{upper}) - (\text{lower}) + 1. Watch:

\sum_{i=1}^{n} i \;\ne\; \sum_{i=0}^{n} i.

The second one has an extra i = 0 term at the front — that's n+1 terms, not n (though here the values happen to total the same, since the extra term is 0). Starting at 0 versus 1 almost always changes the count, so check the bottom limit every time.

Sigma notation is the language of series, and it runs right through higher mathematics and physics:

Compact, precise, and absolutely everywhere in university maths. Learn to read \sum now and a whole library opens up.

See it explained