Solving Quadratics by Factorising
Once you can
factorise a quadratic,
you can solve one. To solve x^2 + bx + c = 0, first rewrite
the left-hand side as a product of two brackets:
x^2 + bx + c = (x + p)(x + q) = 0
Now the whole expression is two things multiplied together, and that product equals zero. This is
where one clean idea does all the work — the null-factor law: if two numbers
multiply to give 0, then at least one of them must be
0. (No two non-zero numbers can multiply to zero.) So:
(x + p)(x + q) = 0 \quad\Longrightarrow\quad x + p = 0 \ \text{ or } \ x + q = 0
Each of those is a simple
equation giving
one solution: x = -p or x = -q. A quadratic
usually has two solutions, called its roots.
Take x^2 + 7x + 12 = 0 We need two numbers that
multiply to 12 and add to 7
— that is 3 and 4. So it factorises and then
splits into two pieces:
(x + 3)(x + 4) = 0 \quad\Longrightarrow\quad x + 3 = 0 \ \text{ or } \ x + 4 = 0
Solving each piece gives the two roots x = -3 or
x = -4. Watch each stage build.
A neat special case: when c is a perfect square subtracted, like
x^2 - 9 = 0, the factors are a
difference of two squares,
(x - 3)(x + 3) = 0, giving roots x = 3 or
x = -3. The same null-factor law finishes the job.
See it explained
Sal Khan works a quadratic equation from factorised form to its roots.