The factor and remainder theorems
When you divide a polynomial f(x) by a linear factor
(x - a), you usually grind through
polynomial division
to find the quotient and remainder. The remainder theorem gives the
remainder instantly — no division needed:
\text{remainder when } f(x) \text{ is divided by } (x - a) \;=\; f(a)
Why? Write the division as
f(x) = (x - a)\,q(x) + r, where
q(x) is the quotient and r the
(constant) remainder. Substitute x = a: the
(x - a) term becomes 0, so
f(a) = r. The remainder is simply the value of the polynomial
at x = a.
The factor theorem is the special case where that remainder is zero.
If f(a) = 0, then dividing by (x - a)
leaves nothing over — so (x - a) divides
f(x) exactly:
f(a) = 0 \iff (x - a) \text{ is a factor of } f(x)
This lets you test a possible factor without dividing at all — just evaluate
f(a) and check whether it is zero. It is the key that unlocks
solving by factorising
for higher-degree polynomials.
See it built
Step through evaluating f(a) for a chosen quadratic and a
chosen a. The value you land on is exactly the remainder — and
when it hits zero, you have found a factor.
See it explained
Sal Khan introduces the polynomial remainder theorem and shows why
f(a) is the remainder.