Factorising Quadratics
Factorising is the reverse of
multiplying polynomials.
Expanding turns (x + 3)(x + 4) into
x^2 + 7x + 12; factorising goes the other way — it takes a
quadratic and writes it as a product of two brackets.
x^2 + 7x + 12 = (x + 3)(x + 4)
This lesson covers the simplest case: a quadratic
x^2 + bx + c whose leading coefficient is
1. (If every term shares a number first, pull out the
common factor
before you start.)
The two-number trick
Look at what happens when we expand (x + p)(x + q) and
collect like terms:
(x + p)(x + q) = x^2 + (p + q)\,x + pq
So the number in front of x is
p + q, and the constant on the end is
pq. To factorise x^2 + bx + c we
simply run that backwards — find two numbers that multiply to
c and add to b:
p \times q = c \qquad\text{and}\qquad p + q = b
Worked example
To factorise x^2 + 7x + 12 we need two numbers that
multiply to 12 and
add to 7. List the factor pairs of
12 and check each sum:
1 \times 12\;(13) \qquad 2 \times 6\;(8) \qquad \boxed{3 \times 4\;(7)}
The pair 3 and 4 works, so
p = 3 and q = 4:
x^2 + 7x + 12 = (x + 3)(x + 4)
Multiply the brackets back out to check — you should land on
x^2 + 7x + 12 again.
See it as an area model
The four products fit together as the area of a rectangle. The
x^2 is a square of side x; the
7x is two strips (3x and
4x); and the 12 is a
3 \times 4 block. Slide them together and the whole rectangle
is (x + 3) wide and (x + 4) tall —
which is exactly the factorisation. Step through it.