Solving Linear Inequalities
Your phone plan caps how much data you can use; a lift has a "maximum 8 people" sign; an online
shop drops the delivery charge once you spend enough. Everyday life is full of limits,
where a whole range of answers is allowed rather than one exact number — and writing and solving
those limits is exactly what an inequality is for.
An equation like 3x + 2 = 11 has exactly one answer:
x = 3, and nothing else fits. But change that
= into a > and everything opens up.
Ask instead 3x + 2 > 11 and there is no single answer — there is a
whole range of them.
Try x = 4: 3(4) + 2 = 14, which really is
bigger than 11. Try x = 100: also works.
Try x = 3.01: works. In fact any number bigger than
3 works, and no number 3 or below does.
The solution isn't a point — it's everything to the right of a line in the sand:
3x + 2 > 11 \;\Longrightarrow\; x > 3
Here's the good news: you solve an inequality almost exactly like an equation
— the same operations to both sides. There is just one twist that trips up nearly
everybody, and we'll make sure it never trips up you.
A linear inequality like 2x + 1 > 7 is solved
almost exactly like an equation: you peel away the operations around
x by doing the inverse operation to
both sides, until x stands alone. If you can
already solve a
two-step equation,
you can already do most of this.
Subtract 1 from both sides, then divide both sides by
2:
2x + 1 > 7 \;\Longrightarrow\; 2x > 6 \;\Longrightarrow\; x > 3
The answer isn't a single number — it's every number bigger than
3, the whole solution set you can picture on a number line.
Drawing the answer: open and filled circles
Because the answer is a range, we picture it on a number line. Mark the
boundary value, then shade an arrow across every number that works. There is a neat convention
for the boundary itself:
-
An open circle (a hollow ring) for < or
> — the boundary is not included. For
x > 3, the number 3 itself does
not satisfy it (3 is not bigger than
3), so we leave the circle hollow.
-
A filled circle (a solid dot) for \le or
\ge — the boundary is included. For
x \ge 3, the number 3 does count, so
the dot is filled in.
Here is x > 3 drawn out — a hollow ring at
3 and an arrow running off to the right, sweeping up every number
bigger than 3. This is the same picture you built when you met
inequalities on a number line.
Worked example: a two-sided inequality
Sometimes x is trapped between two values, written as a
double inequality. The rule is simple: whatever you do, do it to
all three parts at once. Solve:
-2 < 2x \le 6
Divide every part by 2 (a positive number, so no sign flips):
\frac{-2}{2} < \frac{2x}{2} \le \frac{6}{2} \;\Longrightarrow\; -1 < x \le 3
So x is any number greater than -1 and
up to and including 3. On a number line that's an
open circle at -1, a filled
circle at 3, and a bar joining them. Whole numbers that fit:
0, 1, 2, 3 — but not -1 (open) and not
4.
The one extra rule: flipping the sign
Inequalities behave just like equations under adding and
subtracting, and under multiplying or dividing by a positive
number. There is exactly one difference:
If you multiply or divide both sides by a negative number, flip the inequality
sign.
Take 4 > 2 (true) and divide both sides by
-2. Without flipping you'd get
-2 > -1, which is false — but
-2 < -1 is true. Negating both sides reverses their order, just
like reflecting points across 0 on the line (this is the same
mirror you meet with
negative numbers).
So the rule keeps the statement true:
-2x > 6 \;\Longrightarrow\; x < -3
Notice: dividing by -2 turned > into
<. Check it — x = -4 gives
-2(-4) = 8 > 6: yes, -4 < -3 is in the
solution. It really is the numbers below -3.
See it solved
Step through the solution of 2x + 1 > 7 one move at a time —
each line is the inverse operation applied to both sides — then watch the final step show
what happens when the divisor is negative and the sign must flip.
When you multiply or divide both sides by a negative number, you MUST flip the
inequality sign — < becomes
>, and \ge becomes
\le. This is the rule people forget, and forgetting it
gives an answer that is exactly backwards.
-2x < 6 becomes x > -3 — not
x < -3 — because dividing by -2 reverses
the direction. If you're unsure, test a number: x = 0 gives
-2(0) = 0 < 6, true, and 0 > -3 is
indeed the answer that includes it. Two things to hold onto:
-
Adding or subtracting never flips the sign — only multiplying or dividing
by a negative does.
-
If you'd rather never flip at all, there's a trick: keep the
x-term positive. Instead of dividing
-2x < 6 by -2, add
2x to both sides to get 0 < 6 + 2x,
then solve -6 < 2x, i.e. x > -3. Same
answer, no flip needed.
Honestly — yes, often. The real world is full of limits, not exact targets. A speed
limit says v \le 70, not "drive at exactly 70". A budget says
"spend \le \pounds 50". A recipe needs the oven "at least
180°C" (T \ge 180). A bridge must carry
"at most" a certain load; a phrase like "you must be at least 12 to watch this" is
just \text{age} \ge 12. The words "at least"
(\ge) and "at most" (\le)
are inequalities in disguise.
Take it further and you get one of the most useful bits of maths on Earth:
linear programming. Airlines use systems of linear inequalities to schedule
crews and planes; factories use them to squeeze the most output from limited machines and
materials; even hospital diet plans use them to hit nutrition targets at the lowest cost. Each
real-world constraint ("no more than 8 hours", "at least 5 vitamins", "budget under
\pounds X") is one inequality, and the best possible plan lives at
the corner where all those lines meet. Every one of those billion-pound optimisations starts
with the very move you just learned: solve to both sides, and flip when you divide by a
negative.
See it explained
Sal Khan works through solving a two-step inequality, including when to reverse the sign.