Concavity and the Second Derivative
Two curves can both be rising, yet curve in opposite ways: one bows up like a cup, the other
arches over like a dome. This bending is called concavity, and the
second derivative
f''(x) measures it.
- f''(x) > 0: concave up \smile — the curve holds water; the slope is increasing.
- f''(x) < 0: concave down \frown — the curve spills water; the slope is decreasing.
Concavity is just "the slope of the slope": f''>0 means
f' is going up, so the tangents tilt steeper and steeper upward.
Feel the bend
Below is f(x) = x^3 - 3x (bold) with
f''(x) = 6x (thin). Slide the tangent: on the left half, where
f''<0, the curve is a frown — concave down — and the tangent lies
above it; on the right half, where f''>0, it's a smile — concave
up — and the tangent lies below.
Inflection points
An inflection point is where the concavity switches — the curve
changes from cup to dome or back. There f''(x)=0 (or is undefined)
and actually changes sign. For f(x)=x^3-3x:
f''(x) = 6x = 0 \;\Rightarrow\; x = 0, \quad f'' < 0 \text{ left of } 0,\; f'' > 0 \text{ right} \;\Rightarrow\; \text{inflection at } x = 0
Just like with extrema, f''=0 is only a candidate — you must check
the sign really flips.
The second-derivative test
Concavity gives a quick shortcut for classifying a critical point where
f'(c)=0: just check the bend there.
- f''(c) > 0 (concave up, a cup): local minimum.
- f''(c) < 0 (concave down, a dome): local maximum.
- f''(c) = 0: inconclusive — fall back to the first-derivative test.
For f(x)=x^3-3x at x=1:
f''(1)=6>0, concave up, so it's a minimum — matching what the
sign line told us. Step the diagram to see both critical points classified by their bend.
Watch it on Khan Academy