Forecasting

A central bank sets interest rates on a guess about next year's inflation. A warehouse stocks shelves on a guess about next week's demand. A grid operator fires up a power station on a guess about this afternoon's load. Every one of these is a forecast: a statement about the future values x_{T+1}, x_{T+2}, \dots of a series, made from everything observed up to the present time T. This page answers the sharpest possible version of the question: given an ARMA model and the data so far, what single number should I predict, and why that one?

The best forecast is the conditional expectation

Fix a target: we want the forecast \hat x_{T+h} that minimises the mean squared error \mathbb E\big[(x_{T+h} - \hat x_{T+h})^2\big]. There is a clean, universal answer, and it does not depend on the model being ARMA at all:

So "forecasting" reduces to "compute a conditional expectation". For an ARMA model that computation turns into a tidy recipe you can run by hand.

The recipe: plug in the past, zero out the future

Take the model equation, write it for time T+h, and apply the conditional expectation term by term. Three simple rules do all the work:

Applying this walking forward one step at a time — h = 1, then feeding that into h = 2, and so on — generates the whole forecast function \hat x_{T+h} recursively. It is the same substitution every time; only the horizon grows.

Worked example — forecasting an AR(1)

Take the mean-zero model x_t = \phi\, x_{t-1} + \varepsilon_t and stand at time T knowing x_T. Apply the recipe:

\hat x_{T+h} = \phi^{\,h}\, x_T.

With \phi = 0.6 and x_T = 10, the forecasts run 6,\ 3.6,\ 2.16,\ \dots — each a fixed fraction of the last, gliding back toward zero. If the model carries a mean \mu, forecast the deviation and add it back: \hat x_{T+h} = \mu + \phi^h (x_T - \mu).

Forecasts decay to the mean

Because |\phi| < 1 for a stationary series, \phi^h \to 0 and the forecast function slides smoothly to the unconditional mean as the horizon grows: \hat x_{T+h} \to \mu. This is a general fact for any stationary ARMA — the memory of the last observed value fades, and far enough out the best guess is simply "the long-run average". The chart shows an observed series (solid) and its forecast path (the smooth curve) flattening to the mean line: the further ahead you look, the less the present tells you, and the forecast admits it by reverting to the mean.

The rate of the flattening is the persistence: a near-unit-root series (\phi \approx 0.95) coasts back slowly over many steps, while a weakly dependent one (\phi \approx 0.3) snaps to the mean almost at once. An MA(q) model is even blunter — its forecast is exactly the mean for every horizon beyond q, because the model has no memory past q lags.

Most real series are made stationary by differencing before an ARMA is fitted — you model \nabla x_t = x_t - x_{t-1}, not x_t itself (this is the "I" in ARIMA). The classic blunder is to forecast the differenced series and then hand those numbers to your boss. The differences are changes, not levels. You must integrate back: rebuild the level forecasts by cumulatively summing, \hat x_{T+h} = x_T + \sum_{j=1}^{h}\widehat{\nabla x}_{T+j}. Forget this step and a forecast of "demand growth of +2 units" gets reported as "demand of 2 units" — off by the entire current level. Whatever transformation you applied to reach stationarity (differencing, logs, seasonal differencing), the forecast must travel back through its inverse before it means anything.

It looks anticlimactic — you feed a sophisticated model a rich history and it eventually shrugs and says "the average". But that flatness is honesty, not laziness. Under squared-error loss the optimal forecast is the conditional mean, and for a stationary process the conditional mean genuinely does converge to the unconditional mean as information about the distant future decays to nothing. A confident, non-flat long-horizon forecast would be the model lying about how much the present reveals about next year. The interesting content lives at short horizons, where \phi^h is still appreciable — and in the prediction intervals, which keep widening even as the point forecast goes flat.